Function overloading can also be achieved if two or more functions differ only in their return types

Discussion

• ramesh   -Posted on 09 Oct 15
  Function overloading is a process in which functions have same name but either the number of arguments or the data type of arguments has to be different. It does not depend upon the return type of functions because function will return a value when it is called.
  Example:
  class FuncOverloading
  {
    public:
    void sum(int x,int y)
  {
     cout << "\n Sum of two integers ::" << x+y;
  }
  
  void sum(double x,double y,double z)
  {
     cout << "\n Sum of three double variable ::" << x+y+z << endl;
  }
  };
    void main()
  {
     FuncOverloading obj;
     obj.sum(10,20);
     obj.sum(10.1,20.2,30.3);
  
  }
  

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