Numerical - Moment of inertia on semicircle, given radius

Q.  What is the moment of inertia acting on a semicircle of radius 20 mm about the asymmetrical axes?
- Published on 21 Sep 15

a. 125.663 x 103 mm4
b. 17600 mm4
c. 1500 mm4
d. 8800 mm4

ANSWER: 17600 mm4

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    Discussion

  • Sravanthi   -Posted on 24 Nov 15
    - Moment of inertia along asymmetrical is given as 0.11 r4

    Given: Radius = 20 mm

    Formula: 0.11 r4

    Solution:

    Substituting the value of r = 20 mm, we get

    Moment of inertia = 0.11 r4

    = 0.11 x (204)

    = 17600 mm4

    Moment of inertia acting on a semicircle of radius 20 mm about the asymmetrical axes is 17600 mm4

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