Numerical - Power rating of electric motor, given r.p.m & torque - Basic Mechanical Engineering

Discussion

• Rohit Bagh   -Posted on 05 Jun 21
  Mechanical engineering
• Uttamkumar Jagtap   -Posted on 19 Aug 17
  Very nice
  and Very help full sir
  ITI FITTER SEM-IV- FINAL EXAM- JULY-2016
  QUESTION NO. 19
  The tendency of force to rotate an object about an axis is called as torque or moment.
  Given: speed (n) : 1440 r.p.m, torque = 75 Nm, reduction ratio (I) = 1.6 
  Formula: P = 2 p N T / 60
  Solution: 
  i = n / N
  1.6 = 1440 / N
  N = 900 r.p.m
  P = (2 p N T)/ 60
  P = (2 x 3.14 x 900 x 75 ) /60
  P = 423900 /60
  = 7065 W 
  = 7.065 kW
  Power rating of an electric motor is 7.065 kW
  
• jaypalsinh jadeja (asst. professor-amec dhari)   -Posted on 30 May 17
  nice explanation.....
• Sravanthi   -Posted on 06 Nov 15
  The tendency of force to rotate an object about an axis is called as torque or moment.
  
  Given: speed (n) : 1440 r.p.m, torque = 75 Nm, reduction ratio (I) = 1.6
  
  Formula: P = 2 π N T / 60
  
  Solution:
  
  i = n / N
  
  1.6 = 1440 / N
  
  N = 900 r.p.m
  
  P = (2 π x 1440 x 75) / 60
  
  = 7068 W
  
  = 7.068 kW
  
  Power rating of an electric motor is 7.068 kW
  

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