Projectile motion - Range on plane if ball is thrown in upward direction

Q.  A ball is thrown on an inclined surface PQ with a velocity of 50 m/s. What is the range on the plane if the ball is thrown in upward direction? ( θ = 20o, α = 35o)
- Published on 21 Sep 15
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a. 159.32 m
b. 200.12 m
c. 218.89 m
d. 221.31 m

ANSWER: 218.89 m

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    Discussion

  • manoj   -Posted on 27 Oct 19
    The answer should be 189.89 m
  • Manoj   -Posted on 27 Oct 19
    Hi the formula you have used is wrong.
    The formula should be
    Range along the plane =(2 *(u^2) * sina / g cos?) x cos (?+a)
  • Luke   -Posted on 01 Oct 17
    I think deepak is right. I also come up with an answer of 189.89 m

    R=2(50²sin35)(cos55)/
    (9.81cos²20)
    R=189.89 m
  • deepak   -Posted on 16 Sep 17
    ans should be 189.89m
  • Sravanthi   -Posted on 15 Dec 15
    Given: velocity = 50 m/s, θ = 20°, α = 35°

    Formula: Range along the plane =(2 u2 sinα / g cos2θ) x cos (θ+α)

    Solution:

    Range along the plane =(2 u2 sinα x cos (θ+α)) / g cos2θ

    = (2 x 502 x sin 35°x cos (35 + 20)) / 9.81 x cos2 20)

    = 218.89 m

    The range on the plane is equal to 218.89 m when the ball is thrown in upward direction.

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