1) Assume the given statements are true, even if they seem to be at variance from commonly known facts, then decide which of the given conclusion/s logically follows. Statements : I. Some cars can fly II. Rama is a car.
Conclusion : I. Rama can fly II. Rama cannot fly III. Rama can dance IV. Rama can swim
a. Only I follows
b. Either I or II follows
c. Only III follows
d. All I, II, III and IV follow
e. All does not follow
Answer
Explanation

ANSWER: Either I or II follows
Explanation: Statements: I. some cars can fly II. Rama is a car.
This diagram tells us that Rama may fall into any of the two groups – May be he can fly or he cannot. Conclusion: I. Rama can fly II. Rama cannot fly III. Rama can dance  Does not follow IV. Rama can swim  Does not follow


2) In a code language “He gives flower” is written as “nop lui na” , “Bunty gets flower” is written as “dus lap na” and “He gets nothing” is written as “nop lap ugli”. How would “Bunty gets nothing” be written in that code ?
a. dus lap nop
b. na lap ugli
c. lui lap ugli
d. dus lap ugli
e. nop bas dus
Answer
Explanation

ANSWER: dus lap ugli
Explanation: He gives flower > nop lui na  (a) Bunty gets flower > dus lap na  (b) He gets nothing > nop lap ugli  (c) From a and b, we get “flower ===> na”; while from b and c, we get “gets ===> lap”. Hence from b, we get “Bunty ===> dus”. Now from a and c, we get “He ===> nop”. Hence from c, we get “nothing ===> ugli”. Hence we have “Bunty gets nothing ===> dus lap ugli”.


3) A trader has 200 kg of sugar, out of which he sells some with 10% profit and the rest with 25% profit. He gains 15% on the whole. Find the quantity of sugar sold at 25% profit?
a. 120 kg
b. 96.5 kg
c. 84 kg
d. 67 kg
e. None of these
Answer
Explanation

ANSWER: 67 kg
Explanation: Let CP of each kg. of sugar = Rs.1. Cost Price of 200 kg of sugar = Rs.200. Let quantity of sugar sold with 25% profit be X. Therefore, (200 – X) kg of sugar sold at a profit of 10% Then, (125/100 * X) + 110/100 (200 – X) = 115/100 * 200 125X + 110(200 – X) = 115 * 200 125X + 22000 – 110X = 23000 125X – 110X = 23000 – 22000 15X = 1000 X = 1000/15 X = 66.66 kg Quantity of sugar that was sold at 25% gain is 66.66 kg Therefore, option nearby for 66.66 is 67 (d)


4) The incomes and expenditures of P, Q, R are in the ratio of 6 : 8 : 11 and 5 : 8 : 12 respectively. If P saves 1/4th of his income, what is the ratio of the savings of P, Q and R ?
a. 15 : 8 : 2
b. 19 : 7 : 9
c. 7 : 15 : 10
d. 12 : 9 : 17
e. None of these
Answer
Explanation

ANSWER: 15 : 8 : 2
Explanation: Let the incomes of P, Q, R be 6x, 8x, 11x and expenditure be 5y, 8y and 12y respectively. Therefore, savings are : (6x – 5y), (8x – 8y) and (11x – 12y) Now, 6x – 5y = 1/4(6x) 24x – 20y = 6x 18x = 20y x/y = 20/18 = 10 / 9 Savings of P / Savings of Q = 6x – 5y / 8x – 8y = [6(x/y) – 5] / [8(x/y) – 8] = [(6 * 10/9) – 5] / [(8 * 10/9) – 8] = 15/8
Savings of Q / Savings of R = 8x – 8y / 11x – 12y = [8(x/y) – 8] / [11(x/y) – 12] = (8 * 10/9) – 8 / (11* 10/9) – 12 = 8/2 Ratio of savings of P : Q : R = 15 : 8 : 2


5) Ramesh spends 40% of his monthly salary on food, 40% of the remaining on conveyance and clothes and saves 50% of the remaining amount. If his monthly salary is Rs.17,000, how much money does he save every month ?
a. Rs. 3,400
b. Rs. 3060
c. Rs. 2,540
d. Rs.1,880
e. None of these
Answer
Explanation

ANSWER: Rs. 3060
Explanation: Ramesh's monthly income = Rs.17,000 He spends 40% on food. The total money spent on food = 40/100 * 17000 = Rs. 6800 Now, his monthly remaining income = Rs.17000 – Rs.6800 = Rs. 10200 Out of Rs. 10200, he spends 40% on conveyance and clothes. The total money spent on conveyance and clothes = 40/100 * 10200 = Rs. 4080 Now, his monthly remaining income = Rs.10200 – Rs.4080 = Rs. 6120 Out of Rs. 6120, he saves 50%. Amount saved = 50/100 * 6120 = Rs. 3060


6) Neha's mother was four times her age 12 years ago. She will be twice as old as Neha 12 years from now. What is the present age of Neha's mother ?
a. 49 years
b. 57 years
c. 60 years
d. 65 years
e. None of these
Answer
Explanation

ANSWER: 60 years
Explanation: Let Neha's present age be 'x' years. Her age 12 years ago = (x – 12) years Therefore, her mother's age 12 years ago = 4(x – 12) Her mother's present age = 4x – 48 + 12 = 4x – 36 Neha's age after 12 years = x + 12 Her mother's age after 12 years = 4x – 36 + 12 = 4x – 24 4x – 24 = 2(x + 12) 4x – 2x = 24 + 24 x = 24 Therefore, Neha's present age = 24 Her mother's present age = 4x – 36 = 4(24) – 36 = 60 years


7) In a certain code language, “ORANGE” is written as “NTETOO”. How would “BLACK” be written in that language ?
a. ANEIS
b. ANEJT
c. AMEIS
d. ANFIS
e. AMEJS
Answer
Explanation

ANSWER: ANEIS
Explanation: A B C D E F G H I J K L M N O P Q R S T U V W X Y Z


8) A water tank has two pipes to fill water in it. One of the pipes fills water at the rate of 100 litres per hour. The tank is filled by the other pipe in 6 hours and by both pipes together in 4.2 hours. What is the capacity of the tank in litres ?
a. 860 litre
b. 980 litre
c. 1120 litre
d. 1400 litre
e. None of these
Answer
Explanation

ANSWER: 1400 litre
Explanation: Let the time taken by the 1st pipe to fill the tank be x hours. When both the pipes are open, it is given that: 1/x + 1/6 = 1/(4.2) of tank is filled in 1 hour. 1/x + 1/6 = 5/21 21(6 + x) = 30 x 9x = 126 x = 14 hours Therefore, capacity of the tank = 100 * 14 = 1400 litres.


9) Akhil borrowed a certain sum of money at the rate of 6%, 9% and 14% for a period of first two years, next three years and beyond the period of five years respectively. If at the end of nine years, he paid Rs. 8550 as interest, then find the sum of money he had borrowed.
a. Rs. 9,000
b. Rs.14,000
c. Rs.15,000
d. Rs.18,000
e. None of these
Answer
Explanation

ANSWER: Rs. 9,000
Explanation: Let Rs.P be the money borrowed by Akhil. I) R = 6%, T = 2 years Simple Interest of 2 years = PRT/100 = P * 6 * 2/100 = 12P/100 II) R = 9%, T = 3 years Simple Interest of 3 years = P * 9 * 3/100 = 27P/100 III) R = 14%, T = 4 years Simple Interest of 3 years= P * 14 * 4/100 = 56P/100 Therefore, total Simple Interest of 9 years = 12P/100 + 27P/100 + 56P/100 = 95P/100 The total interest paid after nine years = Rs.8550 95P/100 = 8550 Therefore, 95P = 855,000 P = 855,000/95 = Rs. 9,000 Amount of money borrowed by Akhil = Rs. 9,000


10) In a library, there are certain number of books on a shelf, ranging between 75 and 100. 1/6th of them are fiction and 12.5% of them are nonfiction. Find the number of books.
a. 68
b. 72
c. 96
d. Can't be determined
e. None of these
Answer
Explanation

ANSWER: 96
Explanation: 12.5% can be written as 1/8th Since 1/6th of the books are fiction and 1/8th are nonfiction, the total number of books must be exactly divisible by 6 and 8 and should be between 75 and 100. Therefore, 96 is the only number, which fulfills the above criteria. Note that the question doesn't imply that there are ONLY two varieties of books.


11) The average age of 19 boys and the class teacher is 16 years. If the ages of the class teacher and one of the boys are excluded, the average age reduces to 15 years. What is the age of the class teacher ?
a. 40 years
b. 36 years
c. 31 years
d. Data Inadequate
Answer
Explanation

ANSWER: Data Inadequate
Explanation: No. of Persons = 19 boys + 1 class teacher = 20 Average age of 20 people is 16 years. Therefore, total age of 20 persons = 20 * 16 = 320 years  (A) If the class teacher and one boy are excluded, then the average age is 15 years. Therefore, total age of 18 boys = 18 * 15 = 270 years  (B) Age of the class teacher and one boy = 320 – 270 = 50 years. Data is inadequate as the relation between the ages of the boy and the teacher is not provided.


12) Which symbol would be exactly at the middle of the fifth symbol from the right and ninth symbol from the left end of the following sequence of symbols ?
& * ∧ % $ # @ +  ! ∼ μ Ω Δ ± ∈ ≈ ∫ → √ ∞ ∧ @ ↓ ≥ ∈ $ + @
a. ±
b. ∫
c. ≈
d. Ω
e. ∞
Answer
Explanation

ANSWER: ≈
Explanation: & * ∧ % $ # @ +  ! ∼ μ Ω Δ ± ∈ ≈ ∫ → √ ∞ ∧ @ ↓ ≥ ∈ $ + @ The fifth symbol from the right end of the given sequence is “≥”, while the ninth symbol from the left end of the sequence is “”. The symbol at the middle of “≥” and “” is “ ≈ ”.

