Calendar  Quantitative Aptitude (MCQ) questions
Dear Readers, Welcome to Quantitative Aptitude Calendar questions and answers with explanation. These Calendar solved examples with shortcuts and tricks will help you learn and practice for your Placement Test and competitive exams like Bank PO, IBPS PO, SBI PO, RRB PO, RBI Assistant, LIC,SSC, MBA  MAT, XAT, CAT, NMAT, UPSC, NET etc.
After practicing these tricky Calendar multiple choice questions, you will be exam ready to deal with any objective type questions.
1) 15th august 2010 was which day of the week?  Published on 12 Jun 15
a. Thursday
b. Friday
c. Wednesday
d. Sunday
Answer
Explanation

ANSWER: Sunday
Explanation: 15th August 2010 can be written as 2009 + days from 1st January 2010 to 15th August 2010.
=> Total number of odd days in 400 years = 0
Hence, total number of odd days in 2000 years = 0 (as 2000 is a perfect multiple of 400)
Odd in days in the period 20012009: 7 normal years + 2 leap yeas
=> (7*1) + (2*2) = 11
=> Odd days will be 11 (7*1) = 4
Days from January 1 to August 15 in 2010: 31+28+31+30+31+30+31+15
= 227 days.
= 32 weeks and 3 days, this gives additional 3 odd days.
=> Total odd days= 3+4=7
=> 7 odd days=1 week= 0 odd days
=> 0 odd days= Sunday
Thus, 15th August 2010 was a Sunday.


2) What day will be 61 days after today, if today is Monday?  Published on 19 Oct 15
a. Tuesday
b. Thursday
c. Saturday
d. Friday
Answer
Explanation

ANSWER: Saturday
Explanation: The basic concept in a problem involving days is finding the number of odd days. In 61 days:
=> 7 x 8 + 5 = 5 odd days
=> Monday + 5 days = Saturday
Hence 61 days from today will be a Saturday.

