1) Find the principal which yields a simple interest of Rs. 20 and compound interest of Rs. 21 in two years, at the same percent rate per annum?  Published on 06 May 16
a. Rs. 520
b. Rs. 480
c. Rs. 420
d. Rs. 200
Answer
Explanation

ANSWER: Rs. 200
Explanation: SI in 2 years = Rs. 20, SI in 1 year = Rs. 10 CI in 2 years = Rs. 21 % rate per annum = [(CI – SI) / (SI in 1 year)] *100 = [(21 – 20) / 20] * 100 = 5 % p.a. Let the principal be Rs. X Time = T = 2 years % rate = 5% p.a. SI = (PRT/100) 20 = (X*5*2) / 100 X = Rs. 200


2) A sum of Rs. 4000 amounts to Rs. 4600 in 5 years at a certain rate of simple interest. What would be the amount, if the rate of interest is increased by 3 %.  Published on 25 Apr 16
a. Rs. 4900
b. Rs. 5000
c. Rs. 5200
d. Rs. 5600
e. None of these
Answer
Explanation

ANSWER: Rs. 5200
Explanation: Principal = Rs. 4000, Amount = Principal + SI = Rs. 4600 SI = Amount – Principal = 4600 – 4000 = Rs. 600 Given : Principal = Rs. 4000, Time = T = 5 years and SI = Rs. 600 SI =PRT/100 600 = 4000 *R * 5/100 600 = 200R R = 3 % p.a. Now the new interest rate is = 3% + 3% = 6 % p.a. SI = PRT/ 100 = 4000 * 6 * 5/ 100 = Rs. 1200 Amount = Principal + SI = 4000 + 1200 = 5200


3) Akhil borrowed a certain sum of money at the rate of 6%, 9% and 14% for a period of first two years, next three years and beyond the period of five years respectively. If at the end of nine years, he paid Rs. 8550 as interest, then find the sum of money he had borrowed.  Published on 20 Apr 16
a. Rs. 9,000
b. Rs.14,000
c. Rs.15,000
d. Rs.18,000
e. None of these
Answer
Explanation

ANSWER: Rs. 9,000
Explanation: Let Rs.P be the money borrowed by Akhil. I) R = 6%, T = 2 years Simple Interest of 2 years = PRT/100 = P * 6 * 2/100 = 12P/100 II) R = 9%, T = 3 years Simple Interest of 3 years = P * 9 * 3/100 = 27P/100 III) R = 14%, T = 4 years Simple Interest of 3 years= P * 14 * 4/100 = 56P/100 Therefore, total Simple Interest of 9 years = 12P/100 + 27P/100 + 56P/100 = 95P/100 The total interest paid after nine years = Rs.8550 95P/100 = 8550 Therefore, 95P = 855,000 P = 855,000/95 = Rs. 9,000 Amount of money borrowed by Akhil = Rs. 9,000


4) Mr. Karan borrowed a certain amount at 6% per annum simple interest for 9 years. After 9 years, he returned Rs. 8110/. Find out the amount that he borrowed.  Published on 19 Apr 16
a. Rs. 4,900
b. Rs. 5,000
c. Rs. 5,100
d. Rs. 5266
e. None of these
Answer
Explanation

ANSWER: Rs. 5266
Explanation: Let us assume Mr. Karan borrowed amount is Rs. A. (the principal) By formula of simple interest, S.I. = PRT / 100 Where P = The principal, R = Rate of interest as a %, T = Time in years S.I. = (P * 6 * 9)/100 = 54 P/100 Amount = Principal + S.I. 8110 = P + (54P/100) 8110 = (100P + 54P)/100 8110 = 154P/100 P = (8110 * 100)/154 = Rs. 5266.233


5) In how many years, Rs. 200 will produce the same interest @ 5 % as Rs. 900 produce in 2 years @ 3 ½ %?  Published on 06 Apr 16
a. 6.3 years
b. 8.2 years
c. 9 years
d. 12 years
Answer
Explanation

ANSWER: 6.3 years
Explanation: P = Rs 900, R = 3 ½ % = 7/2 %, T = 2 years. Therefore, S.I. = PRT/100 S.I. = Rs. (900 x 7/2 x 2/100) = Rs. 63 Now, P = Rs. 200, S.I. = Rs. 63, R = 5 % Time = ((100 x 63) / (200 x 5) ) years = 6.3 years


6) A certain sum earns simple interest of Rs. 800 in 2 years at a certain rate of interest. If the same sum earns compound interest of Rs. 845 in the same period of 2 years, What must be the rate of interest?  Published on 05 Apr 16
a. 5% p.a.
b. 7.5% p.a.
c. 10% p.a.
d. 12.5% p.a.
Answer
Explanation

ANSWER: 10% p.a.
Explanation: Given: 800 = (P * R * 2) / 100 S.I. For 1 year = Rs. 400 Thus, (840 – 800) = S.I. on Rs. 400 for 1 year 40 = (400 * R * 1) / 100 R = 10% p.a.


7) Find the simple interest on Rs. 78000 at 15(2/5) % per annum for 9 months.  Published on 25 Mar 16
a. Rs. 7804
b. Rs. 8979
c. Rs. 8046
d. Rs. 9009
Answer
Explanation

ANSWER: Rs. 9009
Explanation: P = Rs. 78000, R = 77/5 % p.a and T = 9/12 years = ¾ years Therefore, S.I = (P*R*T)/100 = (78000* 77/5 * ¾ * 1/100) = Rs. 9009


8) Simple interest at x% for x years will come out to be Rs x on a sum of Rs?  Published on 15 Jun 15
a. x
b. 100/x
c. 100/x^{2}
d. 100x
Answer
Explanation

ANSWER: 100/x
Explanation: Formula for Simple Interest:
SI = Principal*Rate*Time
SI= x
Rate= x/100
Time= x
=> x= Principal*(x/100)*x
=>Principal Amount= 100/x


9) What is the minimum number of years upon which SI on Rs 2600 at 6.67% interest rate will be in whole number?  Published on 15 Jun 15
a. 2
b. 6
c. 3
d. 4
Answer
Explanation

ANSWER: 3
Explanation: Simple Interest =Principal * Rate * Time
Principal = 2600 Rs
Interest Rate = 6.67%
=> SI = 2600 * (20/3)*Time
SI of the number will be a whole number for the first time when time is three as denominator of rate is 3.
Hence time should be set to 3 years.


10) What time will be taken by an amount of Rs. 900 to yield Rs. 81 as interest at 4.5% per annum of simple interest?  Published on 19 Oct 15
a. 2 years
b. 1 years
c. 3 years
d. 4 years
Answer
Explanation

ANSWER: 2 years
Explanation: P= Rs 900
Rate = 4.5*
SI= Rs 81
=> SI= Time*P*rate
calculating for rate,
=> Time= SI/rate*P
= 81/4.5%*900
=> 2 years
Thus, it will take 2 years to yield Rs 81.

