# Calendar - aptitude test

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1) 26th January, 1996 was a Friday. What day of the week lies on 26th January, 1997?

a) Saturday
b) Sunday
c) Monday
d) Thursday

SOLUTION :

The year 1996 was a leap year. Hence, it adds 2 odd days. As 26th January, 1996 was a Friday, 26th January, 1997 was a Sunday.

2) The calendar for the year 2001 is same for which of the following year?

a) 2005
b) 2007
c) 2011
d) 2006

SOLUTION :

The total number of odd days from 2001 onwards should be zero.
Now, as an ordinary year adds 1 odd day and a leap year adds 2 odd days, we have:
2001, 2002, 2003, 2005, 2006 – 1 odd day each
2004 – 2 odd days
Hence, at the end of 2006 total number of odd days = 7 or 0
Therefore, the calendar for the year 2001 is repeated in the year 2007.

3) What day of the week was 31st July, 1993?

a) Monday
b) Sunday
c) Saturday
d) Tuesday

SOLUTION :

31st July, 1993 = (1992 years + period from 1st January, 1993 to 31st July, 1993)
1600 years have 0 odd days and 300 years have 1 odd day.
Now, the period from 1900 to 1992 have 69 ordinary years and 23 leap years
= (69*1 + 23*2) = 115 odd days = (16 weeks + 3 days) = 3 odd days.

 January February March April May June July 31 28 31 30 31 30 31

= 212 days = (30 weeks + 2 days) = 2 odd days
Therefore, total number of odd days = 1 + 3 + 2 = 6 odd days.
Therefore, the required day was Saturday.

4) The last day of the century cannot be:

a) Sunday
b) Wednesday
c) Friday
d) Saturday

SOLUTION :

100 years have 5 odd days. Hence the last day of 1st century is a Friday.
200 years have 10 odd days or 1 week + 3 odd days. Hence, the last day of the 2nd century is a Wednesday.
300 years have 15 odd days or 2 week + 1 odd day. Hence, the last day of the 3rd century is a Monday.
400 years have 0 odd days. Hence, the last day of the 4th century is a Sunday.

5) Which of the following year is not a leap year?

a) 1960
b) 2080
c) 2024
d) 2100