Practice Quantitative Aptitude questions on Algebra, covering algebraic expressions, linear and quadratic equations, identities, factorization, exponents, simplification, and word problems involving variables. Takes about 20–25 minutes and is useful for placement tests, TCS NQT, SSC, banking and MBA entrance exams.
Question 1
If 5x + y = 15, 5y + z = 25 and 2z + x = 2, what is the value of x ?
Explanation
From 5x + y = 15: y = 15 - 5x. From 5y + z = 25: z = 25 - 5y = 25x - 50.
Substituting in 2z + x = 2: 50x - 100 + x = 2, so 51x = 102 and x = 2.
Substituting in 2z + x = 2: 50x - 100 + x = 2, so 51x = 102 and x = 2.
Question 2
Find value of a3 + b3 + 3ab, when value of a+b = 1?
Explanation
a³ + b³ = (a + b)³ - 3ab(a + b) = 1 - 3ab, since a + b = 1.
a³ + b³ + 3ab = 1 - 3ab + 3ab = 1.
a³ + b³ + 3ab = 1 - 3ab + 3ab = 1.
Question 3
What will be value of c, if a(a+b+c) = 85; b(a+b+c) = 96; c(a+b+c) = 108?
Explanation
Let S = a + b + c. Adding the three equations: S(a + b + c) = S² = 85 + 96 + 108 = 289, so S = 17.
c × 17 = 108, so c = 10817.
c × 17 = 108, so c = 10817.
Question 4
If 2x +3y = 30 and (x+y)/y = 118, then find the value of 5y + 6x
Explanation
x + yy = 118, so xy + 1 = 118 and xy = 38.
Let x = 3k and y = 8k. 2x + 3y = 6k + 24k = 30k = 30, so k = 1, x = 3 and y = 8.
5y + 6x = 40 + 18 = 58.
Let x = 3k and y = 8k. 2x + 3y = 6k + 24k = 30k = 30, so k = 1, x = 3 and y = 8.
5y + 6x = 40 + 18 = 58.
Question 5
If x + 4y = 21 and x = -3y, then y =
Explanation
x = -3y, so x + 4y = -3y + 4y = y = 21.
y = 21.
y = 21.
Question 6
P can choose 1 of 2 methods of payment: an annual salary of $35,000 & no commission or annual salary $10,000 & 20% commission on annual sales. What are her annual sales to give her the same pay with either?
Explanation
Let the annual sales be S. Both methods give the same pay: 35,000 = 10,000 + 20100S.
20100S = 25,000, so S = $125,000.
20100S = 25,000, so S = $125,000.
Question 7
A man works for 5 days. His pay for each day is 1 12 times that of the previous day. If his total wages are $422 for the 5 days, what was his pay for the second day?
Explanation
Let the first day's pay be a. The pay for the 5 days is a, 1.5a, 2.25a, 3.375a and 5.0625a.
Sum = 13.1875a = 422, so a = 32.
Pay for the second day = 1.5 × 32 = $48.
Sum = 13.1875a = 422, so a = 32.
Pay for the second day = 1.5 × 32 = $48.
Question 8
A car dealer sold x used cars and y new cars during May. If the number of used cars sold was 10 greater than the number of new cars sold, which of the following expresses this relationship?
Explanation
The number of used cars x is 10 greater than the number of new cars y, so x = y + 10.
Question 9
T has some money. M gives him 8 cents. F then gives him the same amount as T has at that time. Then G gives him $2.00 & T spends 50 cents. If he has $3.20 left how much did T have to begin with?
Explanation
Let T have x cents to begin with. After M gives 8 cents he has x + 8. F gives him the same amount, so he has 2(x + 8).
Then G gives him 200 cents and he spends 50 cents: 2(x + 8) + 200 - 50 = 320.
2(x + 8) = 170, so x + 8 = 85 and x = 77 cents.
Then G gives him 200 cents and he spends 50 cents: 2(x + 8) + 200 - 50 = 320.
2(x + 8) = 170, so x + 8 = 85 and x = 77 cents.
Question 10
P said "Give me 3 of your marbles & I will have as many as you." Q said "If you give me 3 of yours, I will have twice as many as you". With how many marbles did P start out?
Explanation
Let P have p marbles and Q have q marbles.
P's statement: p + 3 = q - 3, so q = p + 6.
Q's statement: q + 3 = 2(p - 3), so p + 6 + 3 = 2p - 6 and p = 15.
P started with 15 marbles.
P's statement: p + 3 = q - 3, so q = p + 6.
Q's statement: q + 3 = 2(p - 3), so p + 6 + 3 = 2p - 6 and p = 15.
P started with 15 marbles.
Question 11
If 2 + 1/x = 5 - 2/x then x =
Explanation
2 + 1x = 5 - 2x, so 1x + 2x = 3, that is 3x = 3.
x = 1.
x = 1.
Question 12
If a,b and c are non zero numbers and a + b = c, which of the following is equal to 1?
Explanation
a + b = c, so c - b = a.
c - ba = aa = 1.
c - ba = aa = 1.
Question 13
If x + 3y = 18 and x/y = 3 then x =
Explanation
xy = 3, so x = 3y.
x + 3y = 18 gives 3y + 3y = 18, so y = 3 and x = 9.
x + 3y = 18 gives 3y + 3y = 18, so y = 3 and x = 9.
Question 14
M decided to give S $8 for each problem S got correct. S would pay M $5 for each S got wrong. There were 26 problems. After getting the marks, noone paid the other any money. How many problems did S get right?
Explanation
Let S get r problems right and w wrong. r + w = 26.
Nobody paid anything, so 8r = 5w. Then 8r = 5(26 - r), so 13r = 130 and r = 10.
S got 10 problems right.
Nobody paid anything, so 8r = 5w. Then 8r = 5(26 - r), so 13r = 130 and r = 10.
S got 10 problems right.
Question 15
The cost of 3 sandwiches, 7 cups of coffee & 4 pieces of cake is $10.20; the cost of 4 sandwiches, 8 cups of coffee & 5 pieces of cake is $12.25. What is the cost of 1 sandwich, 1 coffee & 1 piece of cake?
Explanation
Let the costs of a sandwich, a coffee and a cake be s, c and k.
3s + 7c + 4k = 10.20 and 4s + 8c + 5k = 12.25.
Subtracting the first from the second: s + c + k = 12.25 - 10.20 = 2.05.
The cost is $2.05.
3s + 7c + 4k = 10.20 and 4s + 8c + 5k = 12.25.
Subtracting the first from the second: s + c + k = 12.25 - 10.20 = 2.05.
The cost is $2.05.
Question 16
If n is negative, all EXCEPT which of the following must also be negative?
Explanation
If n is negative, an odd power of n, n⁵ or n³, is negative, and the reciprocal of a negative number, 1n⁵, is also negative.
But n² is positive, so 1n² is positive. So 1n² is the exception.
But n² is positive, so 1n² is positive. So 1n² is the exception.
Question 17
If x is greater than zero and less than 1, which of the following is the largest?
Explanation
For 0 < x < 1, take x = 0.5: 1x² = 4, 1x = 2, x = 0.5 and x² = 0.25.
Dividing by a smaller positive number gives a larger value, so 1x² is the largest.
Dividing by a smaller positive number gives a larger value, so 1x² is the largest.
Question 18
If 0 < x < 1, which of the following is the largest?
Explanation
For 0 < x < 1, take x = 0.5: x = 0.5, 2x = 1, x² = 0.25 and x + 1 = 1.5.
x + 1 is greater than 1, whereas x < 1, x² < 1 and 2x < 2. Also x + 1 > 2x because x < 1.
So x + 1 is the largest.
x + 1 is greater than 1, whereas x < 1, x² < 1 and 2x < 2. Also x + 1 > 2x because x < 1.
So x + 1 is the largest.
Question 19
X has 10 pairs of socks. If he loses 7 individual socks, what is the greatest number of pairs he can have left?
Explanation
X has 10 pairs, that is 20 socks. To keep the greatest number of pairs, the 7 lost socks should come from as few pairs as possible.
7 socks are lost from 4 different pairs (3 pairs entirely and one single sock from the fourth), so 4 pairs are affected.
Pairs left = 10 - 4 = 6.
7 socks are lost from 4 different pairs (3 pairs entirely and one single sock from the fourth), so 4 pairs are affected.
Pairs left = 10 - 4 = 6.
Question 20
On 31st May, the sale of candy was $385 m, 7% of total yearly candy sales. Candy sales for the year =
Explanation
$385 m is 7% of the yearly sales.
Yearly sales = 3857 × 100 = $5500 m.
Yearly sales = 3857 × 100 = $5500 m.
Question 21
If we divide a two-digit number by the sum of its digits, we get 6 as a quotient and 2 as a remainder. Now if we divide it by the product of its digits, we get 5 as the quotient and 2 as the remainder. What is the number?
Explanation
Let the number be 10a + b. 10a + b = 6(a + b) + 2, so 4a - 5b = 2.
Also 10a + b = 5ab + 2.
Try a = 3, b = 2: 4 × 3 - 5 × 2 = 2, and 10 × 3 + 2 = 32 = 5 × 6 + 2.
The number is 32.
Also 10a + b = 5ab + 2.
Try a = 3, b = 2: 4 × 3 - 5 × 2 = 2, and 10 × 3 + 2 = 32 = 5 × 6 + 2.
The number is 32.
Question 22
The value of -3-(-10) is how much bigger than the value of -10-(-3) ?
Explanation
-3 - (-10) = -3 + 10 = 7 and -10 - (-3) = -10 + 3 = -7.
The difference = 7 - (-7) = 14.
The difference = 7 - (-7) = 14.
Question 23
103 + 105 =
Explanation
10³ + 10⁵ = 1000 + 100000 = 101,000.
Question 24
X and Y packed several boxes. If Y packed 60 percent of the total number of boxes, what was the ratio of the number of boxes X packed to the number of boxes Y packed?
Explanation
Y packed 60% of the boxes, so X packed 100 - 60 = 40%.
X : Y = 40 : 60 = 2 : 3.
X : Y = 40 : 60 = 2 : 3.
Question 25
A suit at 40% off is now selling for the reduced price of $144. What was the original price of the suit ?
Explanation
The suit is 40% off, so the selling price is 60% of the original price.
60% of the original price = $144, so the original price = 14460 × 100 = $240.
60% of the original price = $144, so the original price = 14460 × 100 = $240.