Puzzles Practice Test Questions - Logical Reasoning

Floor 1 is the top and floor 6 is the lowermost. H is on an even floor other than 4 and not on the lowermost floor 6, so H is on floor 2. M is on floor 3. K is on an even floor with J immediately below it, so J's floor number is one more than K's. K cannot be on floor 2 (H) or floor 6 (nothing below it), so K is on floor 4 and J on floor 5. Floors 1 and 6 remain for G and L; L is not on the topmost floor, so L is on floor 6 and G on floor 1. So J lives on floor 5.

S is on floor 3, so R (odd floor, not 5) is on floor 1. U is on an even floor with P immediately above it, and P is not on the top floor. U on floor 2 would put P on floor 3, which is S's floor, and U on floor 6 leaves no floor for P, so U is on floor 4 and P on floor 5. Floors 2 and 6 remain for Q and T; T is not on the top floor, so T is on floor 2 and Q on floor 6. The floor immediately above S is floor 4, where U lives.

Counting from the bottom: only C is below E, so C is 1st and E 2nd. Only B is above F, so B is 7th and F 6th. One box is between E and G, so G is 4th, and D, immediately above G, is 5th. A takes the remaining place, 3rd. Order from the bottom: C, E, A, G, D, F, B. Between A and F are G and D, so two boxes.

Two boxes are above J, so J is 5th from the bottom, and K, immediately above J, is 6th. One box is between J and L with L below J, so L is 3rd. Only H is below N, so H is 1st and N 2nd. I is not at the top, so I is 4th and M 7th. Order from the bottom: H, N, L, I, J, K, M. The box immediately below L is N.

C is on Wednesday. Four people are between B and F and neither is on Sunday, so they are on Monday and Saturday; F is not after B, so F is on Monday and B on Saturday. D and G are on consecutive days, and the only two free consecutive days are Thursday and Friday, so D is on Thursday and G on Friday. Tuesday and Sunday remain; A is not on Sunday, so A is on Tuesday and E on Sunday. Only E has an exam after B, so the answer is 1.

P is on Monday and M on Friday. Three people are between K and N, N is after K and neither is on Monday, so (K, N) is (Tuesday, Saturday) or (Wednesday, Sunday). L is immediately after O. In the second case the free days are Tuesday, Thursday and Saturday, and no two of them are together, so that case fails. So K is on Tuesday and N on Saturday; O and L take Wednesday and Thursday, and J takes Sunday. Between O (Wednesday) and N (Saturday) are L and M, so 2 people.

D is faster than all four others, so D is the fastest. B is faster than only one runner, so B is fourth. E is faster than B but slower than C, so the order from the fastest is D, C, E, B, with A the slowest. C is faster than E, B and A, so three runners are slower than C.

Q is the lightest, and R is heavier than only one bag, so R is fourth. S is heavier than R but lighter than T and P, so S is third, with T and P in the top two places. P is not the heaviest, so T is first and P second. Two bags, T and P, are heavier than S.

Row 1: no one is to the right of E, so E is at the right end (place 5 from the left). C is third to the left of E, at place 2. A is not at an end and B is to the immediate right of A, so A is at place 3 and B at place 4, leaving D at place 1. Row 2: one person is to the left of C, so one person is to the right of X, and X is at place 4. W is behind A, at place 3. Y is not at an end, so Y is at place 2. V and Z take the ends, and Z is to the right of V, so V is at place 1 and Z at place 5. Row 1 is D, C, A, B, E and Row 2 is V, Y, W, X, Z. The person to the immediate left of X is W, and A sits directly in front of W.

Row 1: K is at the left end (place 1). Two people are between K and M, so M is at place 4, and N, to the immediate right of M, is at place 5. L is not next to K, so L is at place 3 and J at place 2. Row 2: R is behind M, at place 4. One person is between R and P, so P is at place 2. T is not at an end, so T is at place 3. Q is to the left of S, so Q is at place 1 and S at place 5. Row 1 is K, J, L, M, N and Row 2 is Q, P, T, R, S. The person to the immediate right of P is T, and L sits directly in front of T.

F is on Thursday. Two people are between F and B, so B is on Monday or Sunday; B is not on Monday, so B is on Sunday. D-E and C-G are pairs of consecutive days with one person between E and C. The free days are Monday, Tuesday, Wednesday, Friday and Saturday, and the only arrangement that works is D on Tuesday, E on Wednesday, C on Friday and G on Saturday (F, on Thursday, is the one person between E and C). A takes Monday. Only A has an exam before D, so the answer is 1.

L is on Friday. One person is between L and N, so N is on Wednesday or Sunday. M-K and O-P are pairs of consecutive days with exactly two people between P and M. If N were on Wednesday, the free days would be Monday, Tuesday, Thursday, Saturday and Sunday, and the pairs would have to be Monday-Tuesday and Saturday-Sunday, which leaves three or five people between P and M, not two. So N is on Sunday. Then M on Monday, K on Tuesday, O on Wednesday and P on Thursday give two people (K and O) between M and P, and J takes Saturday. After O come P, L, J and N, so 4 people.

The girls are A, C, E and G. Of these, C and G brought sandwiches, so A and E brought fruit. Both A and E drank tea. So the two girls are A and E.

The science students are Q, R, T and U. Of these, Q and T play cricket. Neither Q nor T wears glasses. So the two students are Q and T.

D is on Sunday. Three people are between A and B and neither is on Sunday, so they are on (Monday, Friday) or (Tuesday, Saturday). G is immediately before A, so A is not on Monday. If A were on Friday, G would be on Thursday and B on Monday, leaving Tuesday, Wednesday and Saturday, where C, E and F cannot have three consecutive days. If A were on Saturday, G would be on Friday and B on Tuesday, leaving Monday, Wednesday and Thursday, which also fails. So A is on Tuesday, G on Monday and B on Saturday, and C, E and F take Wednesday, Thursday and Friday. Between A (Tuesday) and D (Sunday) are C, E, F and B, so 4 people.

M is on Sunday. Four people are between K and O and neither is on Sunday, so K and O are on Monday and Saturday. J is immediately before O, so O is not on Monday: O is on Saturday, J on Friday and K on Monday. L, N and P are on three consecutive days in that order, which must be Tuesday, Wednesday and Thursday. Between L (Tuesday) and O (Saturday) are N, P and J, so 3 people.

Four persons live between C and F, and C is not on the top or ground floor, so (C, F) is (2, 7) or (6, 1). If C were on floor 6, E would be on floor 5 or 7 and G would have to live above E, so E is on 5 and G on 7; A must then be next to G on floor 6, which is C's floor, so this case fails. So C is on floor 2 and F on floor 7. E is next to C and D lives below E, so E is on floor 3 and D on floor 1. Two persons live between B and E, so B is on floor 6. G and A take floors 4 and 5, and A is on an odd floor, so A is on floor 5 and G on floor 4. From the ground floor: D, C, E, G, A, B, F. Between C (2) and A (5) live E and G, so the statement "Two persons live between C and A" is true. D is on floor 1, two floors below E; B is on floor 6; and G is below A, so the other statements are false.

Three persons live between P and S with P above S, so (S, P) is (1, 5), (2, 6) or (3, 7). S is on an odd floor but not the ground floor, so S is on floor 3 and P on floor 7. R is immediately below P, on floor 6. One person lives between R and U, so U is on floor 4. V is immediately above T and U is above T, so of the free floors 1, 2 and 5, T is on floor 1 and V on floor 2. Q takes floor 5. From the ground floor: T, V, S, U, Q, R, P. Q (5) is immediately below R (6), so that statement is true. One person lives between V and U, T is on floor 1 and P is on floor 7, so the other statements are false.

D got the job in 2002 and B got it immediately before D, so B got it in 2001. A, E and C got jobs in three consecutive years in that order, which must be 2003, 2004 and 2005. So C got the job in 2005.

S bought a car in 2018 and P immediately before, in 2017. T and Q bought in consecutive years with Q after T; the only consecutive free years are 2019 and 2020, so T bought in 2019 and Q in 2020. R took 2016, which agrees with R not buying in 2020. So Q bought a car in 2020.

From the bottom: only R is above U, so R is 7th and U 6th. Three boxes are between U and Q, so Q is 2nd, and only S is below Q, so S is 1st. Places 3, 4 and 5 remain for P, T and V, with V immediately above P. T is not immediately below U, so T is not 5th; T is 3rd, P 4th and V 5th. Above V are U and R, so 2 boxes.

Only F is below D, so F is 1st and D 2nd from the bottom. One box is above B, so B is 6th. G is below B with one box between them, so G is 4th, and E, immediately above G, is 5th. A and C take places 3 and 7; A is not at the top, so A is 3rd and C 7th. Between A and B are G and E, so 2 boxes.

L travelled in 2015. Two people travelled between K and M with M later, so (K, M) is (2011, 2017) or (2013, 2019). With (2011, 2017) the free years are 2013, 2019 and 2021, and O and N cannot have exactly one person between them. With (2013, 2019) the free years are 2011, 2017 and 2021: O in 2017 and N in 2021 works (M is between them), and J takes 2011. So K travelled in 2013.

D joined in 2016 and E immediately after D, in 2018. Two people joined between D and B, so B joined in 2022. A and F have one person between them with A first; the free years are 2014, 2020 and 2024, so A joined in 2020 and F in 2024, with B between them. C took the remaining year, 2014.

E, C and B hold three consecutive ranks in that order. D is at the lowest rank (5), so E, C, B and A share ranks 1 to 4. A is not at the top, so the block E, C, B takes ranks 1, 2 and 3 and A is fourth. The order is E, C, B, A, D, so C is at the second rank.

S is at rank 1. T, Q and R hold three consecutive ranks in that order among ranks 2 to 6. If they were at 3, 4 and 5, U would have to be at 2 or 6, which is not allowed. If they were at 2, 3 and 4, P and U would take 5 and 6; U is not at 6, so P would be at 6, which is also not allowed. So T, Q and R are at 4, 5 and 6, U is at 3 and P at 2. R is at the lowest rank.

From the bottom: three boxes are below L, so L is 4th, and one box is above K, so K is 6th. Two boxes are between K and N, so N is 3rd. P is immediately above O; of the free places 1, 2, 5 and 7, only 1 and 2 are together, so O is 1st and P 2nd. M is below J, so M is 5th and J 7th. Between P and M are N and L, so two boxes.

From the bottom: one box is below T, so T is 2nd, and two boxes are above S, so S is 5th. One box is between S and U, so U is 3rd or 7th; R is above U, so U is not at the top and U is 3rd. W is immediately above V; of the free places 1, 4, 6 and 7, only 6 and 7 are together, so V is 6th and W 7th. R is above U, so R is 4th and Q 1st. Between Q and R are T and U, so two boxes.

C is taller than F; F is taller than B and D; B is taller than D; D is taller than A; A is taller than E. So the order from the tallest is C, F, B, D, A, E, and E is the shortest.

J is taller than O, O is taller than M, M is taller than N, N is taller than L and L is taller than K. So the order from the tallest is J, O, M, N, L, K, and the third tallest is M.

F is in Flat B on Floor 2 or 3 with A immediately below it in Flat B, and A is not on Floor 1, so F is in Flat B on Floor 3 and A in Flat B on Floor 2. C is on an odd floor with no one else on that floor; Floor 3 already has F, so C is on Floor 1. E is two floors from C in the same flat, so E is on Floor 3, and since Flat B on Floor 3 is F's, E and C are both in Flat A. Flat B on Floor 1 is vacant. B and D need a whole floor, which can only be Floor 4: B in Flat A and D in Flat B. The second vacant flat is Flat A on Floor 2. So A lives in Flat B on Floor 2.

P is in Flat A on Floor 2 or 3 with T immediately below it in Flat A. U and R need a whole floor (U in Flat A, R in Flat B), and U is not on Floor 1. Q is on an even floor and S is two floors from Q in the same flat, with no one else on S's floor. If P were on Floor 3, U and R would have to take Floor 4; Q could then only be in Flat B on Floor 2, and S would need Flat B on Floor 4, which is R's. So P is in Flat A on Floor 2 and T in Flat A on Floor 1. If U and R took Floor 4, the same clash would happen, so U and R are on Floor 3. If Q were on Floor 4, S would be on Floor 2 with P, which is not allowed, so Q is in Flat B on Floor 2 and S in Flat B on Floor 4, with Flat A on Floor 4 vacant. Flat B on Floor 1 is the second vacant flat. So R lives in Flat B on Floor 3.

Only one order meets every condition: 1 Calendar, 2 Notes, 3 Music, 4 Maps, 5 Photos, 6 Weather, 7 Camera, 8 Wallet. Check it: three apps (Photos, Weather, Camera) are between Maps and Wallet; one app is before Notes and one after Camera; one app (Maps) is between Music and Photos, and Photos is just after Maps; Notes is before Music; Weather is after Calendar and before Camera; one app (Camera) is between Weather and Wallet; Calendar is before Notes; Photos is not just before Maps. So Calendar was downloaded first.

Only one order meets every condition: 1 Pasta, 2 Raita, 3 Dal, 4 Halwa, 5 Biryani, 6 Soup, 7 Pulao, 8 Kheer. Check it: two dishes (Halwa, Biryani) are between Dal and Soup; no dish is before Pasta and none after Kheer; one dish (Dal) is between Raita and Halwa, and Raita is just before Dal; Pulao is after Biryani and before Kheer; Halwa is before Biryani. So Kheer was cooked last.

C is older than only B, so B is the youngest and C is sixth. E is younger than only F, so F is the eldest and E is second. G is older than four others, so G is third. A and D take fourth and fifth, and D is younger than A, so A is the fourth eldest.

T is younger than only S, so S is the eldest and T second. U is older than only R, so R is the youngest and U sixth. Q is older than only two others, so Q is fifth. V and P take third and fourth, and P is younger than V, so V is the third eldest.

Five people are between B and E, so they are on Monday and Sunday. G is immediately before B, so B is on Sunday, G on Saturday and E on Monday. C is on Wednesday. F and D are on consecutive days among Tuesday, Thursday and Friday, so F is on Thursday and D on Friday, and A is on Tuesday. Between A (Tuesday) and G (Saturday) are C, F and D, so three people.

Four people are between K and P, so they are on (Monday, Saturday) or (Tuesday, Sunday); N is on Tuesday, so K and P are on Monday and Saturday. L is immediately after K, so K is on Saturday, L on Sunday and P on Monday. J and O are on consecutive days and M takes the remaining day among Wednesday, Thursday and Friday. M is not on Friday, and M on Thursday would separate J and O, so M is on Wednesday, J on Thursday and O on Friday. Between N (Tuesday) and K (Saturday) are M, J and O, so three people.