1) If in a game of 80, P can give 16 points to Q and R can give 20 points to P, then in a game of 150, how many points can R give to Q?  Published on 06 Jul 15
a. 48
b. 60
c. 54
d. 90
Answer
Explanation

ANSWER: 60
Explanation: When P scores 80, Q scores 64. When R scores 80, P scores 60 Hence, when R scores 150, Q scores (60 * 64 * 150) / (80 * 80) = 90 Therefore, in a game of 150, R can give 60 points to Q.


2) If X can run 48m and Y 42m, then in a race of 1km, X beats Y by:  Published on 06 Jul 15
a. 140m
b. 125m
c. 100m
d. 110m
Answer
Explanation

ANSWER: 125m
Explanation: When X runs 48m, Y runs 42m. Hence, when X runs 1000m, Y runs (1000 * 42) / 48 = 875m X beats Y by 125m.


3) If in a race of 80m, A covers the distance in 20 seconds and B in 25 seconds, then A beats B by:  Published on 06 Jul 15
a. 20m
b. 16m
c. 11m
d. 10m
Answer
Explanation

ANSWER: 16m
Explanation: The difference in the timing of A and B is 5 seconds. Hence, A beats B by 5 seconds. The distance covered by B in 5 seconds = (80 * 5) / 25 = 16m Hence, A beats B by 16m.


4) In a race, A beats B by 15 metres and C by 29 metres. If B and C run over the course together, B wins by 15 metres. What is the length of the course?  Published on 15 Jun 15
a. 225m
b. 120m
c. 220m
d. 160m
Answer
Explanation

ANSWER: 225m
Explanation: Let X be the length of the course
according to the question, A beats B by 15 metres and C by 29 metres
Applying this, If A runs X metres, B runs (X15) and C runs ( X29) metres.
B and C together run, B runs X metres and C runs (X15)
=> If B runs 1 metre, C runs X15/X
=> B runs X15 m, C runs (X15/x) * (X15)
APPLYING THIS, X29 = (X15)(X15) / X
Solving,
X^{2} 29X= X^{2} – 30 X + 225 X = 225
Thus, length of the course is 225 metres.


5) For a race a distance of 224 meters can be covered by P in 28 seconds and Q in 32 seconds. By what distance does P defeat Q eventually?  Published on 19 Oct 15
a. 26m
b. 32m
c. 24m
d. 28m
Answer
Explanation

ANSWER: 32m
Explanation: This is a simple speed time problem. Given conditions:
=>Speed of P= 224/28 = 8m/s
=>Speed of Q=224/32 = 7m/s
=>Difference in time taken = 4 seconds
Therefore, Distance covered by P in that time= 8m/s x 4 seconds = 32 metres

