Explanation: Normal stress acting on the plane of maximum shear stress will be, (Taking compression as positive)

σ_{n} = (σ_{x}± σ_{y}) / 2 =(50 – 20) / 2 = +15

that is 15 MPa compression.

2) A spring of radius 1 cm obeys Hooke's law. A mass of 2 kg is attached to the spring. Calculate the extension of the spring. The spring constant k is 110 N/m - Published on 19 Oct 15

Explanation: According to the Hooke's law force applied to extend or compress a spring is directly proportional to change in length of the spring. Therefore F = – kX where k is spring constant. By using this formula and taking force applied F = mg = 2 × 9.8 =19.6 N and k = 110 N/m we can fine X.

3) Poisson's ratio is the ratio of ______(Marks: 01) - Published on 19 Oct 15

Explanation: The ratio of lateral strain to longitudinal strain has a constant value and it is called as Poisson's ratio. Poisson's ratio is denoted by v

4) What is stress? (Marks: 01) - Published on 19 Oct 15

a. internal resistance offered by a body against deformation

b. external resistance offered by a body against deformation

c. internal force offered by a body against deformation

d. external force offered by a body against deformation