A container contains 30 liters of milk. From this container 5 liter of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?

Options
- 18.45 liter
- 23.44 liter
- 17.36 liter
- 21.87 liter

CORRECT ANSWER : 17.36 liter

Discussion Board
Quant

It''s not (30-25) in the above formula. It is (30-5).

Rajesh Jojari 09-30-2022 10:48 AM

Detail sol of above problem

My method is different from that of formula (it is better if you remember that formula in comp. Exams).

So, 30L milk is in container, 0L water in container initially.

5L of milk taken out and replaced by same quantity of water ,
Milk left=(30-5)=25L.,. Water =5L

Now this is repeated twice , but now 5L of mixture will be taken out (Now in container there is mixture of milk &water)

So, 1) Milk in the mixture taken out=(25/30)*5=4.16L
So milk left= (25-4.16)= 20.84L. , Water = 9.16L (30-20.84)

2) M:W= 20.84:9.16

Quantity of milk taken out now from mixture= (20.84/20.84+9.16)*5 or (20.84/30)*5= 3.4733L of milk taken out now

So milk left now =( 20.84- 3.4733)= 17.367L

So milk left after second step= 17.367 L , water left = 12.6L

Ashutosh Sharma 06-5-2020 12:32 AM

sol question 1 correction

Q=30((30-5)/30)^3
Q=17.36

shivam chaudhary 12-9-2018 01:10 AM

sol question 1

initial quantity of milk(A)=30L
amount of milk replaced by water in one operation (B)=5L
no of operation=3
formula: (Q)Quantity of milk left after n operations/A =[(A-B)/A]^n
Q=30[(30-25)/30]^3
on solving we get Q=17.36


Shivam chaudhary 12-9-2018 01:05 AM

Give me detailed solution of that question

how?

Rasika Kulkarni 11-24-2016 02:03 AM

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