Aptitude model placement papers with solution - set 6

ANSWER: A. 42

Solution: 1 man is equivalent to 2 boys in work capacity. 12 men + 18 boys = 12 x 2 + 18 = 42 boys.

Let the required number of boys be x. So Total number of people doing work = 21 men x 2 (according to work capacity) + x boys.

Taking respective ratios as required:

Given:

=> Hours 50:60
=> Minutes per hour 9: 15/2
=> Work 1:2
=> People: 42: 42 + x
=> 50 x 9 x 1 x (42+x) = 60 x 15/2 x 2 x 42
=> 42 +x = 84

x = 42

ANSWER: D. 9 minutes

Solution: Let B be turned off after X minutes.

Part of water will be filled by A + B in x minutes + After tap B is closed rest filled by A in (30-x) minutes = 1

=> x/(time taken to fill the container by each separately) + 30 - x/(time taken to fill the container by A alone) = 1
=> x(2/75 + 1/45) + (30-x)2/75 = 1
=> 11x + 180 – 6x = 225

Therefore, x = 9 minutes

ANSWER: D. 26.67 km

Solution: Distance travelled by each of them is to be made equal.

=> Distance travelled walking = Distance covered cycling.

Let after 4 hours of walking, A walk for x hours more before B catches up with him.

=> Distance = Speed * Time

(4+x)4 = 10x

x = 8/3

Therefore, It takes B 8/3 hours to catch up with A. Distance: 8/3 x 10 = 80/3 km = 26.67

ANSWER: C. 4 kmph

Solution: Simple Division.
No stream current mentioned.
Trick question.
Speed= Distance/Time.
Speed= 3/4 km / (11.25/60) hr
Therefore, Speed = 4 km/hr

ANSWER: B. Rs 6600

Solution: Let initial amount that the man invests be A

Let x be the capital

=> Profit on 1st investment + Profit on 2nd investment + Profit on 3rd investment

=> S.I. = P X R X T

=> Remainder of capital = 1 - 1/3 - 1/4 = 5/12x (x being the capital)

=> a*1/3 *7/100 + 1/4 *a * 8/100 + 5x/12*a* 10/100 = 561

Therefore, a = 6600

ANSWER: C. Rs 8920

Solution: Use the formula Amount = Principal Amount(1 + R/100)ⁿ

Where r is rate and t is time in years

=>13,380 = P(1+R/100) ² --(1)

=>20,070 = P(1+R/100) ⁶ --(2)

=> 1.5 = (1+R/100) ⁴

=> P = Rs 8920

ANSWER: B. T
Solution: Let a be the side of square b be the side of triangle and r be the radius of the circle:

It is given that perimeter of all the three figures is same
=> 4a = 3b = 2πr
=> a = 3b/4
=> r= 3b/2π

Areas: Now that we have all the three sides in terms of b we can equate and compare areas of the three equations:

Square: 9b²/16
Triangle: b²/4
Circle: 9b²/4π

From this we can say that Area (Circle) > Area (Square) > Area (Triangle)

ANSWER: B. 12.36%

Solution: Let old radius be 1r

As the radius has increased by 6%, the new radius = 1.06 r

New area = π (1.06r)²
=1.1236πr²

Increase: πr² (1.1236) - πr²

=> 0.1236πr² /πr²

=> 12.36%

ANSWER: D. 4.6

Solution: In the given question we have taken average of 6 numbers taken 2 at a time which makes 3 numbers.

=> 3.95 (Average of 1st and 2nd number)
=> 3.85 (Average of 3rd and 4th number)
=> 3.4 (Average of 5th and 6th number)

3.95 = (3.4 + 3.85 + x)/3

x = 4.6

ANSWER: D. 2124

Solution: The following pattern has been followed in this question:

16 = 15 x 1 + 1

34 = 16 x 2 + 2

We have established that previous number is multiplied by increasing numbers (1,2,3,4.....) and then added by increasing numbers (1,2,3,4...)

105 = 34 x 3 + 3

424 = 105 x 4 + 4

2125 = 424 x 5 + 5

=> 2124 is incorrect