Question 1
Pankaj is facing west. He turns 45° in the clockwise direction and then again turns 180° in the same (clockwise) direction, after which he turns 270° in the anti-clockwise direction. Which direction is he facing now?
Explanation
West = 270° bearing. +45° (CW) = 315°. +180° (CW) = 495° = 135°. -270° (CCW) = 135 - 270 = -135° = 225°
225° bearing corresponds to South-West
225° bearing corresponds to South-West
Question 2
Shweta moved a distance of 75 metres towards the north. She then turned to the left and walked about 25 metres, turned left again and walked 80 metres. Finally, she turned to the right at an angle of 45°. In which direction was she moving finally?
Explanation
North, then left turn faces West, then left turn faces South
Turning right (clockwise) by 45° from South gives South-West
Turning right (clockwise) by 45° from South gives South-West
Question 3
Neha walked 2 km west of her house and then turned south, covering 4 km. Finally, she moved 3 km towards east and then again 1 km west. How far is she from her initial position?
Explanation
Starting at (0,0): West 2 km → (-2,0). South 4 km → (-2,-4). East 3 km → (1,-4). West 1 km → (0,-4)
Distance from start = 4 km (due south)
Distance from start = 4 km (due south)
Question 4
Facing towards North, Ravi walks 35 m. He then turns left and walks 55 m. He again turns left and walks 35 m. How far is he from his original position and towards which direction?
Explanation
North 35 m → left turn faces West, walks 55 m → left turn faces South, walks 35 m
The two 35 m legs (North then South) cancel out, leaving a net displacement of 55 m West
The two 35 m legs (North then South) cancel out, leaving a net displacement of 55 m West
Question 5
Ram starts moving from a point, facing East. After walking 15 m, he turns to his left and walks 25 m, before turning to his right. Then he walks a distance of 35 m, then turns to his right and stops after walking a further distance of 25 m. Find how far Ram is from his starting point.
Explanation
East 15 m: (15, 0). Left turn (North) 25 m: (15, 25). Right turn (East) 35 m: (50, 25). Right turn (South) 25 m: (50, 0)
Distance from start = √502 + 02 = 50 m
Distance from start = √502 + 02 = 50 m
Question 6
A man is facing towards East and turns through 45° clockwise, again 180° clockwise and then turns through 270° anti-clockwise. In which direction is he facing now?
Explanation
Total clockwise turn = 45° + 180° = 225°; then 270° anti-clockwise = -270°
Net turn = 225° - 270° = -45° (i.e. 45° anti-clockwise from East)
45° anti-clockwise from East = North-East
Net turn = 225° - 270° = -45° (i.e. 45° anti-clockwise from East)
45° anti-clockwise from East = North-East
Question 7
Seven villages A, B, C, D, E, F and G are situated as follows:
E is 2 km to the west of B
F is 2 km to the north of A
C is 1 km to the west of A
D is 2 km to the south of G
G is 2 km to the east of C
D is exactly in the middle of B and E.
Which two villages are the farthest from one another?
E is 2 km to the west of B
F is 2 km to the north of A
C is 1 km to the west of A
D is 2 km to the south of G
G is 2 km to the east of C
D is exactly in the middle of B and E.
Which two villages are the farthest from one another?
Explanation
Let A=(0,0). F=2km north of A: F=(0,2). C=1km west of A: C=(-1,0). G=2km east of C: G=(1,0). D=2km south of G: D=(1,-2).
D is the midpoint of B and E, and E is 2km west of B: solving gives B=(2,-2), E=(0,-2).
Checking each option: F-E=4, D-C≈2.83, F-B=√(4+16)≈4.47, G-E=√5≈2.24.
The farthest pair is F and B (≈4.47 km).
D is the midpoint of B and E, and E is 2km west of B: solving gives B=(2,-2), E=(0,-2).
Checking each option: F-E=4, D-C≈2.83, F-B=√(4+16)≈4.47, G-E=√5≈2.24.
The farthest pair is F and B (≈4.47 km).
Question 8
There are four towns P, Q, R and T. Q is to the South-west of P, R is to the east of Q and South-east of P, and T is to the north of R in line with QP. In which direction of P is T located?
Explanation
Let P=(0,0). Q is South-west of P: Q=(-1,-1). R is East of Q and South-east of P: R=(1,-1) (satisfies both).
T is North of R and on the line QP extended (the line y=x): with x=1 on that line, T=(1,1), which is indeed directly North of R=(1,-1).
T relative to P=(0,0): T=(1,1) → North-East
T is North of R and on the line QP extended (the line y=x): with x=1 on that line, T=(1,1), which is indeed directly North of R=(1,-1).
T relative to P=(0,0): T=(1,1) → North-East
Question 9
Gopal started from the house towards West. After walking a distance of 30 metres, he turned towards right and walked 20 metres. He then turned left and, moving a distance of 10 metres, turned to his left again and walked 40 metres. He now turned to the left and walked 5 metres. Finally, he turned to his left. In which direction was he walking now?
Explanation
Start facing West. Turn right → North. Turn left → West. Turn left → South. Turn left → East. Finally, turn left (no walk) → North.
He ends up facing North.
He ends up facing North.
Question 10
Rasik walked 20 m towards north. Then he turned right and walked 30 m. Then he turned right and walked 35 m. Then he turned left and walked 15 m. Finally, he turned left and walked 15 m. In which direction and how many metres is he from the starting position?
Explanation
Start (0,0), facing North. North 20: (0,20). Turn right (East), 30: (30,20). Turn right (South), 35: (30,-15). Turn left (East), 15: (45,-15). Turn left (North), 15: (45,0).
Final position (45,0) is 45 m due East of the start.
Final position (45,0) is 45 m due East of the start.
Question 11
A child is looking for his father. He went 90 meters to the east before turning to his right. He went 20 meters before turning to his right again to look for his father at his uncle's place 30 meters from this point. His father was not there. From there, he went 100 meters to his north before meeting his father in a street. How far did the son meet his father from the starting point?
Explanation
Track position from start (0,0): East 90m → (90,0). Turn right (South), 20m → (90,-20). Turn right (West), 30m → (60,-20). North 100m → (60,80).
Distance from start = √602 + 802 = √3600 + 6400 = √10000 = 100 m
Distance from start = √602 + 802 = √3600 + 6400 = √10000 = 100 m
Question 12
Raju starts from point A and walks 1 km towards south, turns left and walks 1 km. Then he turns left again and walks 1 km. Now he is facing?
Explanation
Start facing South. Turn left (from South, left turn = East). Turn left again (from East, left turn = North).
He is now facing North.
He is now facing North.
Question 13
A man is facing north. He turns 45 degrees in the clockwise direction and then another 180 degrees in the same direction and then 45 degrees in the anticlockwise direction. Find which direction he is facing now.
Explanation
Start facing North (0°). Turn 45° clockwise: 45°. Turn 180° clockwise: 45+180=225°. Turn 45° anticlockwise: 225-45=180°, which is South.
Question 14
P started from his house towards west. After walking a distance of 25 m, he turned to the right and walked 10 m. He then again turned to the right and walked 15 m. After this he is to turn right at 135° and to cover 30 m. In which direction should he go?
Explanation
Start facing West. Turn right → facing North, walk 10m. Turn right again → facing East, walk 15m. Turn right by 135° from East (bearing 90°): 90 + 135 = 225°, which is South-West.
Question 15
Ravi left home and cycled 10 km towards South, then turned right and cycled 5 km, and then again turned right and cycled 10 km. After this he turned left and cycled 10 km. How many kilometres will he have to cycle to reach his home straight?
Explanation
Start (0,0) facing South, walk 10: (0,-10). Turn right (West), walk 5: (-5,-10). Turn right (North), walk 10: (-5,0). Turn left (West), walk 10: (-15,0).
Distance back to home (0,0) from (-15,0) = 15 km
Distance back to home (0,0) from (-15,0) = 15 km
Question 16
Read the information given below to answer these questions. A, B, C, D, E, F, G, H and J are nine houses. C is 2 km east of B. A is 1 km north of B and H is 2 km south of A. G is 1 km west of H while D is 3 km east of G and F is 2 km north of G. I is situated just in the middle of B and C while E is just in the middle of H and D.
Distance between E and I is:
Distance between E and I is:
Explanation
Let B=(0,0). C=2km east of B: C=(2,0). A=1km north of B: A=(0,1). H=2km south of A: H=(0,-1). G=1km west of H: G=(-1,-1). D=3km east of G: D=(2,-1).
I = midpoint of B and C = (1,0). E = midpoint of H and D = (1,-1).
Distance E to I = √02 + 12 = 1 km
I = midpoint of B and C = (1,0). E = midpoint of H and D = (1,-1).
Distance E to I = √02 + 12 = 1 km