Formula for determining size of equivalent pipe for two pipes - Fluid Mechanics

Q.  What is the formula for determining the size of equivalent pipe for two pipes of lengths L1, L2 and diameters d1, d2 respectively?

Where,
L = L1 + L2
- Published on 05 Aug 15

a. (L / d) = (L1 / d1) + (L2 / d2)
b. (L / d2 ) = (L1 / d12) + (L2 / d22)
c. (L / d3) = (L1 / d13 ) + (L2 / d23)
d. (L / d5) = (L1 / d15 ) + (L2 / d25)

ANSWER: (L / d5) = (L1 / d15 ) + (L2 / d25)

Related Content

 

    Discussion

  • martin ugalde   -Posted on 18 Jan 21
    I HAVE AN 8-INCH PARALLEL WITH A 6-INCH SAME LENGTH. WHAT IS THE EQUIVALENT DIAMETER?

    THANKS
  • Rs   -Posted on 04 Oct 15
    Nice
  • Pankaj   -Posted on 30 Sep 15
    When several pipes of different lengths and diameters are connected in series, then it is called as compound pipe. If this compound pipe is replaced by a pipe of uniform diameter and the same length as that of compound pipe, then it is called as equivalent pipe and the uniform diameter of the equivalent pipe is called as equivalent diameter.

    Equivalent pipe has the same discharge and loss of head as that of the compound pipe.
    Therefore, equivalent pipe for two pipes of lengths L1, L2 and diameters d1, d2 respectively,

    [Head Loss in Equivalent Pipe] = [Head loss in pipe 1] + [Head loss in pipe 2]

    hLe = hf1 + hf2

    (f L Q2) / (12.1 d5) = (f1 L1 Q2) / (12.1 d15) + (f2 L2 Q2) / (12.1 d25)

    If f = f1 = f2, then we get

    (L / d5) = (L1 / d15) + (L2 / d25)

➨ Post your comment / Share knowledge


Enter the code shown above:

(Note: If you cannot read the numbers in the above image, reload the page to generate a new one.)
▲