# Loss at the exit of a pipe - Fluid Mechanics

Q.  What is the correct formula for loss at the exit of a pipe?
- Published on 04 Aug 15

a. hL = 0.5 (V2 / 2g)
b. hL = (V2 / 2g)
c. hL = (2 V2 / g)
d. hL = (4 V2 / g)

ANSWER: hL = (V2 / 2g)

#### Discussion

• saichanda   -Posted on 10 May 19
IAM from civil completed diploma plz send important for ecet exam
• abhilash   -Posted on 20 Aug 17
It is 0.5(V^2/2g)
• Pankaj   -Posted on 21 Oct 15
- The head loss at the exit of pipe is different from head loss at the inlet.

- Exit loss does not depend upon the alignment or the geometry of the pipe. Therefore, the outlet loss coefficient is also independent of fitting place, size and shape of the pipe.

- The head loss due to sudden expansion in pipe from area A1 to A2 is give by,

hL = ((V1)2 / (2g)) x (1 – (A1 / A2))2

- At the exit of the pipe, A2 becomes infinity

Therefore, the equation becomes,

hL = V2 / 2g
• Pankaj   -Posted on 30 Sep 15
The energy losses occur in flow through pipe in order to overcome hydraulic resistance. These losses in pipe are classified into two categories.

1. Major losses
2. Minor losses

The losses which occur due to friction in pipe, then they are called as major losses. Major losses are calculated by Darcy-Weisbach formula.

hf = (4 f L V2) / (2 g D)

and the losses which occur due to disturbance in the flow pattern are called as minor losses. Theses losses occur due to sudden contraction or expansion in pipe, bends in pipe, valves and fittings etc.

Head loss at the exit of pipe is given by,

hL = V2 / 2g

Where, V is the velocity of the flowing fluid.

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