Numerical - Calculate self capacitance of the coil

Q.  At 2 MHz, the resonance is obtained with a resonating capacitance value of 12 pF and at 400 kHz, the resonance is obtained with resonating capacitance value of 320 pF. Then the self capacitance of the coil is
- Published on 16 Sep 15

a. 0.62 pF
b. 0.83 pF
c. 1.2 pF
d. 1.5 pF

ANSWER: 0.62 pF

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    Discussion

  • Sumanth    -Posted on 27 May 17
    Self capacitance={c1-4c2}/3. None of the option is correct how u will solve pls send me

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