Numerical - Driving point admittance for given impedance

Q.  In the circuit, the driving point impedance is (s + 5) / (s2 + 5s + 1). Hence, the driving point admittance of the circuit is __________
- Published on 06 Oct 15
One


a. (s + 5)
b. (s2 + 5s + 1)
c. (s + 5) x (s2 + 5s + 1)
d. (s2 + 5s + 1) / (s + 5)

ANSWER: (s2 + 5s + 1) / (s + 5)

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