Numerical - Elevator - Reactive force acting on man

Q.  A man of 60 kg moves in a lift of constant velocity 5 m/s. What is the reactive force acting on the man by the elevator?
- Published on 18 Sep 15

a. 888 N
b. 588 N
c. 288 N
d. Zero



  • Sravanthi   -Posted on 15 Dec 15
    Given: velocity = 5 m/s, weight of man = 60 kg

    Formula: Force = mg + ma


    According to Newton's 2nd law, rate of change of linear momentum is directly proportional to impressed force.

    Force = mg + ma

    As lift moves with constant velocity, acceleration (a) =0

    Substituting the given values,

    Force = mg

    = 60 x 9.81

    = 588.6 N

    The reactive force acting on the man by the elevator is 588.6 N.

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