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Numerical on curvilinear motion
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Engineering Mechanics
Q. A particle moves along a path y = x
2
– 6x + 200. If v
x
= 6 m/s , what is the value of v
y
at x = 30?
- Published on 18 Sep 15
a.
354 m/s
b.
300 m/s
c.
324 m/s
d.
None of the above
ANSWER: 324 m/s
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Discussion
Sravanthi
-Posted on 15 Dec 15
Given:
y = x
2
– 6x + 200 is the path of moving particle, v
x
= 6 m/s
Solution:
y = x
2
– 6x + 200 ---- (differentiate this equation)
v
y
= 2x v
x
– 6 v
x
= 2 (30) (6) – 6 (6)
= 324 m/s
Value of vy at x = 30 is 324 m/s
➨
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