Q.  What is the proof resilience of a square bar of 2500 mm2  and 200 mm long, when a load of 150 kN is induced gradually?
(Take E = 150 x 103 Mpa)

- Published on 21 Sep 15

a. 45 J
b. 8 J
c. 5.3 J
d. 6 J

#### Discussion

• Zubair    -Posted on 10 Apr 23
Oh! That's really given in clear form..
My concept regarding to proof resilience is clear now.
Thanks
• Sravanthi   -Posted on 24 Nov 15
Proof resilience: It is the maximum strain energy which is stored within elastic limit. It is also called as strain energy.

Given: Area of square bar = 2500 mm2 , gradual load applied = 150 kN, length of bar 200 mm, E = 150 x 103 Mpa

Formula: Proof resilience = (σ2 / 2E) x volume = (σ2 / 2E) x AL

Solution:

1) Stress = Applied load / Area = 150 x 103 / 2500 = 60 N/mm2

2) Proof resilience = (σ2 / 2E) x AL

Substituting the given values, we get

= (602 / 2 x 150 x 103) x (2500 x 200)

= 6000 N-mm

= 6 Joule

Proof resilience of a square bar is 6 Joule.

## ➨ Post your comment / Share knowledge Enter the code shown above:

(Note: If you cannot read the numbers in the above image, reload the page to generate a new one.)