# Numerical - Thrust in connecting rod, given piston effort - Theory of Machines - 1

Q.  Calculate the thrust in connecting rod, if piston effort is 200 kN and crank makes an angle of 45o from TDC. Assume obliquity ratio = 3.5
- Published on 06 Aug 15

a. 900.80 kN
b. 204.20 kN
c. 195.87 kN
d. 970.02 kN

#### Discussion

• Vamsikrishhh   -Posted on 03 Aug 18
Good
• Sravanthi   -Posted on 19 Oct 15
- Thrust or force along connecting rod is given as FQ = FP / cos Φ

- FP is the piston effort i.e is the net force acting on the piston along the line of stroke.

Solution:

Given: Piston effort = 200 kN, crank angle θ= 45° , obliquity ratio = 3.5

1) To find the value of Φ

sin Φ = sin θ / n

Therefore, Φ = sin-1 (sin 45 / 3.5) = 11.65°

Substituting the given values we get,

FQ = FP / cos Φ

FQ = 200 x 103 / cos 11.65

= 204.20 kN

Therefore, force acting on connecting is 204.20 kN

## ➨ Post your comment / Share knowledge

Enter the code shown above:

(Note: If you cannot read the numbers in the above image, reload the page to generate a new one.)