# Numerical - Wahl's factor, given spring index

Q.  What is the Wahl's factor if spring index is 6?
- Published on 14 Sep 15

a. 1.477
b. 0.995
c. 1.252
d. None of the above

#### Discussion

• Glenn   -Posted on 09 Oct 19
1.30375
• Sravanthi   -Posted on 06 Nov 15
- Spring: An elastic or resilient body which deforms or deflects when load is applied and regains its original shape when load is removed.

- Wahl shear stress concentration factor (Kw): This factor accounts both direct shear stress and torsional shear stress along with the curvature effect stress.

- The formula to calculate this factor is: Kw= [(4C - 1) / (4C - 4)] + [0.615 / C]

Given: Spring index (C) = 6

Solution:

Wahl factor (Kw) = [(4C - 1) / (4C - 4)] + [0.615 / C]

Substituting the value of spring index (C) = 6, we get

(Kw) = [(4C - 1) / (4C - 4)] + [0.615 / C]

= [(4 x 6) – 1) / (4 x 6) – 4)] + [0.615 / 6]

= 1.252

Wahl shear stress concentration factor (Kw) = 1.252

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