# Projectile motion - Range on plane if ball is thrown in upward direction

Q.  A ball is thrown on an inclined surface PQ with a velocity of 50 m/s. What is the range on the plane if the ball is thrown in upward direction? ( θ = 20o, α = 35o)
- Published on 21 Sep 15

a. 159.32 m
b. 200.12 m
c. 218.89 m
d. 221.31 m

#### Discussion

• manoj   -Posted on 27 Oct 19
The answer should be 189.89 m
• Manoj   -Posted on 27 Oct 19
Hi the formula you have used is wrong.
The formula should be
Range along the plane =(2 *(u^2) * sina / g cos?) x cos (?+a)
• Luke   -Posted on 01 Oct 17
I think deepak is right. I also come up with an answer of 189.89 m

R=2(50²sin35)(cos55)/
(9.81cos²20)
R=189.89 m
• deepak   -Posted on 16 Sep 17
ans should be 189.89m
• Sravanthi   -Posted on 15 Dec 15
Given: velocity = 50 m/s, θ = 20°, α = 35°

Formula: Range along the plane =(2 u2 sinα / g cos2θ) x cos (θ+α)

Solution:

Range along the plane =(2 u2 sinα x cos (θ+α)) / g cos2θ

= (2 x 502 x sin 35°x cos (35 + 20)) / 9.81 x cos2 20)

= 218.89 m

The range on the plane is equal to 218.89 m when the ball is thrown in upward direction.

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