1) 36 is divided in 2 parts such that 8 times the first part added to 3 times the second part makes 203. What is the first part?
a. 15
b. 19
c. 23
d. None of these
Answer
Explanation

ANSWER: 19
Explanation: Let the first part be x. 8x + 3 (36 – x) = 203 8x + 108 – 3x = 203 5x + 108 = 203 5x = 95 x = 19


2) The least number which is a multiple of 11 and when divided by 3, 5 and 9 leaves 2 as remainder:
a. 297
b. 319
c. 407
d. None of these
Answer
Explanation

ANSWER: 407
Explanation: The L.C.M. of 3, 5 and 9 is 45. Hence, the number is of the form (45a + 2). The least value of ‘a’ for which (45a + 2) is multiple of 11 is 9. Therefore, the number is 407.


3) What is the fourth proportional to the numbers 2, 5, 8.
a. 40
b. 20
c. 15
d. 10

4) Find the value of x when y = 5, if x varies directly as 4y1 and x = 14 when y = 2.
a. 38
b. 35
c. 10
d. 28
Answer
Explanation

ANSWER: 38
Explanation: Let z = 4y1 When x = 14, y = 2, z = (4*2) – 1 = 7 Now, x varies directly as z = 4y1 When y = 5, z = (4*5) – 1 = 19 x 14 7 y  19
Therefore, x = (14*19)/7 = 38


5) If a cloth merchant sells ‘a’ metres of cloth for Rs.x, then what is the selling price of ‘b’ metres of cloth?
a. Rs.(b*x)
b. Rs.{(b*x)/a}
c. Rs.{(a*b)/x}
d. None of these
Answer
Explanation

ANSWER: Rs.{(b*x)/a}
Explanation: Cost of ‘a’ metres of cloth = Rs.x. Therefore, each metre of cloth costs Rs. (x/a). The cost of ‘b’ metres of cloth = Rs. b*(x/a) = Rs. {(b*x)/a}


6) A leak at the bottom of the tank can empty the tank in 5 hours, while an inlet pipe can fill the same tank at the rate of 6 litres per minute. When the tank is full, the inlet is opened and the tank gets empty in 8 hours due to the leakage. Find the capacity of the tank.
a. 1800 litres
b. 3600 litres
c. 4800 litres
d. 5760 litres
Answer
Explanation

ANSWER: 4800 litres
Explanation: The capacity of the tank is given by C = (p*q*r)/(r – p) litres Where, p = time in which the leakage can empty the tank in hours = 5 hours q = rate at which the inlet fills the tank in lph = 6*60 = 360 lph r = time in which the tank gets emptied in hours = 8 hours Hence, C = (5*360*8)/(8 – 5) C = 4800 litres


7) Vessel ‘A’ contains 150 litres of mixture of milk and water in the ratio of 3:1. Vessel ‘B’ contains 200 litres of the mixture in the ratio of 5:2. If the mixture from both the vessels are poured into vessel ‘C’, find the ratio of the resulting mixture.
a. 15 : 7
b. 8 : 3
c. 15 : 2
d. 143 : 53
Answer
Explanation

ANSWER: 143 : 53
Explanation: As vessel A contains 150 litres of mixture of milk and water in the ratio 3:1, the quantity of milk is 3*150/4 litres, and that of water is 150/4 litres. Similarly, as vessel B contains 200 litres of mixture of milk and water in the ratio 5:2, the quantity of milk is 5*200/7, and that of water is 2*200/7 litres. After mixing the total quantity is 350 litres. The quantity of milk is {(3*150/4) + (5*200/7)} = 7150/28 The quantity of water is {(150/4) + (2*200/7)} = 2650/28 The ratio of the resulting mixture = 7150/2650 = 143 : 53


8) If Ajay drives at 4/5th of his usual speed to his office, he is 6 minutes late. What is his usual time to reach his office?
a. 36
b. 24
c. 30
d. 18
Answer
Explanation

ANSWER: 24
Explanation: Let t be his usual time to reach his office and v be his usual speed. v = d/t ……….(d is the distance Ajay travels while going to his office) vt = d At v1 = 4v/5 ; t1 = t + 6 4v/5 = d/(t + 6) 4v/5* (t + 6) = d 4v/5* (t + 6) = vt On solving we get, t = 24 minutes


9) If a boat is rowed downstream for 50 km in 5 hours and upstream for 24 km in 6 hours, what is the speed of the boat and the river?
a. (7 , 3) km/hr
b. (6 , 4) km/hr
c. (10 , 4) km/hr
d. None of these
Answer
Explanation

ANSWER: (7 , 3) km/hr
Explanation: If x: speed of boats man in still water y: speed of the river Downstream speed (Ds) = x + y Upstream speed (Us) = x – y x = (Ds + Us) / 2 y = (Ds – Us) / 2 In the above problem Ds = 10 ; Us = 4 x = (10 + 4) / 2 = 14/2 = 7 km/hr y = (10  4)/2 = 6/2 = 3 km/hr


10) If Ajay completes a certain work in 8 days and Vijay can complete the same work in 24 days, find the time in which the work will be completed if both Ajay and Vijay work together.
a. 12 days
b. 16 days
c. 6 days
d. 10 days
Answer
Explanation

ANSWER: 6 days
Explanation: On working together Ajay and Vijay can complete the work in (8*24)/(8 + 24) = 192/32 = 6 days


11) What fraction is equivalent to 0.8% ?
a. 1/125
b. 2/25
c. 4/5
d. None of these
Answer
Explanation

ANSWER: 1/125
Explanation: 0.8% = 0.8/100 = 8/1000 = 4/500 = 2/250 = 1/125


12) Akshay buys a motorcycle for Rs.25000. If he decides to sell the motorcycle for a profit of 7%, find the selling price.
a. 27000
b. 26750
c. 26000
d. 25750
Answer
Explanation

ANSWER: 26750
Explanation: Profit = %profit/100 * cost price P = 7/100 * 25000 = 1750. Selling price = cost price + profit = 25000 + 1750 = Rs.26750


13) Vijay says that his weight is between 75kg and 85 kg. But his younger sister disagrees with Vijay and says that his weight is greater than 70kg but less than 80 kg. Vijay’s mother says that his weight cannot be greater than 78 kg. If all the three predictions are correct, what is the average of different probable weights of Vijay?
a. 75
b. 80
c. 78.5
d. 76.5
Answer
Explanation

ANSWER: 76.5
Explanation: Vijay’s opinion:  75 < Vijay’s age < 85 Sister’s opinion:  72 < Vijay’s age < 82 Mother’s opinion:  Vijay’s age < 78 As all the above three conditions are true, the values satisfying them are 76 & 77. Average value = (76 + 77)/ 2 = 76.5


14) If the ratio of the ages of Shweta and Veena was 5:6 six years ago and it will become 10:11 in 4 years from now, then find the present age of Veena.
a. 16
b. 18
c. 10
d. 12
Answer
Explanation

ANSWER: 18
Explanation: Let the ages of Shweta and Veena 6 years ago be 5x and 6x. Present ages is (5x + 6) and (6x +6) respectively, and their ages 4 years from now will be (5x + 10) and (6x + 10). (5x + 10) / (6x + 10) = 10 /11 55x + 110 = 60x + 100 5x = 10 x = 2 Present age of Veena = (6x + 6) = (6*2 + 6) = 18 years


15) If the length is increased by 25%, by what percent the width of a rectangle should be decreased so as to keep the area same.
a. 25%
b. 20%
c. 30%
d. 10%
Answer
Explanation

ANSWER: 20%
Explanation: Let the original length be l and the width be b Therefore, the area = l*b Now, as the length is increased by 25%, the new length is (1.25*l) and let the new width be x. As the area is same, 1.25*l*x = l*b x = b/1.25 = 0.8b Therefore, the width is to be decreased by 20%.


16) A company pays 12.5% dividend to its investors. If an investor buys Rs.50 shares and gets 25% on investment, at what price did the investor buy the shares?
a. 6.25
b. 25
c. 50
d. 12.5
Answer
Explanation

ANSWER: 25
Explanation: Dividend on 1 share = (12.5 * 50)/100 = Rs.6.25 Rs.25 is income on an investment of Rs.100 Rs.6.25 is income on an investment of Rs. (6.25 * 100)/25 = Rs.25


17) In how many different ways can the letters of the word ‘GEOMETRY’ be arranged so that the vowels always come together?
a. 720
b. 4320
c. 2160
d. 40320
Answer
Explanation

ANSWER: 4320
Explanation:
There are in all 8 letters in the given word of which 3 are vowels. As the vowels should always be together, considering the 3 vowels as one letter, there are in all 6
letters which can be arranged in 6! ways = 720 Also the 3 vowels can be arranged in 3! ways = 6 Total number of arrangements = 720*6 = 4320


18) Tickets numbered 1 to 50 are mixed and one ticket is drawn at random. Find the probability that the ticket drawn has a number which is a multiple of 4 or 7?
a. 9/25
b. 9/50
c. 18/25
d. None of these
Answer
Explanation

ANSWER: 9/25
Explanation: S = {1, 2, 3, … , 49, 50} E = {4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 7, 14, 21, 35, 42, 49} n(S) = 50 n(E) = 18 P(E) = n(E)/n(S) = 18/50 = 9/25


19) Rashmi and Rakhi were partners in a business. Rashmi contributed 2/3rd of the capital for 20 months and Rakhi received 3/5th of the total profit. What was the time duration of Rakhi’s investment in the business?
a. 45 months
b. 30 months
c. 60 months
d. 10 months
Answer
Explanation

ANSWER: 60 months
Explanation: Ratio of the capital = 2 : 1 Ratio of the profit = 2 : 3 Let the duration of Rakhi’s investment be x months. (2*20) : (1*x) = 2 : 3 x = 60 months


20) 34, 45, 56, 67,78, _ ?
a. 81
b. 83
c. 89
d. None of these
Answer
Explanation

ANSWER: 89
Explanation: No explanation is available for this question!


21) CX, EV, GT, IR, ?
a. JQ
b. LO
c. KP
d. MN
Answer
Explanation

ANSWER: KP
Explanation: No explanation is available for this question!


22) 5, 25, 61, 113, ?
a. 187
b. 189
c. 185
d. 181
Answer
Explanation

ANSWER: 181
Explanation: No explanation is available for this question!


23) 1, 9, 17, 33, 49, 73, _ .
a. 98
b. 97
c. 89
d. 90
Answer
Explanation

ANSWER: 97
Explanation: No explanation is available for this question!


24) How much time does a train 125 metres long running at 60 km/hr take to pass a pole?
a. 6s
b. 2.08s
c. 7.5s
d. 8s
Answer
Explanation

ANSWER: 7.5s
Explanation: 60 km/hr = 60 * 5/18 = 16.67 m/s Speed = distance/time; v = d/t 16.67 = 125/t t = 7.5s


25) If a pipe can fill a tank in 6 hours, find the part of tank it fills in one hour.
a. 1/6
b. 2/3
c. 1/2
d. None of these
Answer
Explanation

ANSWER: 1/6
Explanation: Let the capacity of the tank be C litres. Time to fill the tank = 6 hours Hence, in 1 hour C/6 litres gets filled. Therefore, 1/6th part of the tank gets filled in one hour.


26) A group of 55 adults and 70 children go for trekking. If there is meal for either 70 adults or 90 children and if 28 adults have their meal, find the total number of children that can be catered with the remaining food.
a. 42
b. 54
c. 90
d. 70
Answer
Explanation

ANSWER: 54
Explanation: As there is meal for 70 adults and 28 have their meal, the meal left can be catered to 42 adults. Now, 70 adults = 90 children 7 adults = 9 children Therefore, 42 adults = 54 children Hence, the meal can be catered to 54 children.

