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H.C.F L.C.M 1
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What is the highest number of 4 digits which will leave a remainder of 1 when divided by any of the numbers 6, 9, 12, 15 and 18?
Options
- 9980
- 9901
- 9980
- 9971
CORRECT ANSWER : 9901
Discussion Board
Maths
LCM of 6,9,12,15,18 is 180,
Then we need to find highest 4 digit number.
So, 9999/180 = rem 99
Then, sub the dividend and rem
9999-99 = 9900
Now, in question the remainder will be 1 so we need to add 1
Then, 9900+1 = 9901 so we get a rem as 1
So, the correct and option is B)9901
NANDHINI V 06-3-2024 05:56 AM
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