# Time and Distance - Aptitude test, questions, shortcuts, solved example videos

Video on Time and Distance - shortcuts, tips and tricks

## Time and Distance

Time & Distance is one of the most important chapters for any entrance exam. The concepts of this chapter help you in dealing effectively with the other two chapters i.e “Trains” and “Boats & Streams”.

Important Points to Remember

1) Speed is defined as the distance travelled per unit time.
 Speed = Distance Time

2) If same distance X is travelled at two different speeds S1 & S2, then average speed is calculated by,
 Average Speed (Sa) = (2S1S2) (S1 + S2)

3) Two bodies A and B move between two points P & Q. One starts from P and goes to Q while the other starts from Q and goes to P. They meet on the way and reach their destinations in time ta and tb respectively after meeting . Their speeds Sa & Sb are given by,

 Sa = tb Sb ta

4) When two bodies move in opposite direction, their speeds are added to find the relative speed.

SR = S1 + S2

5) When two bodies move in same direction, their speeds are subtracted to find the relative speed.

SR = S1 – S2

Conversion of Units

It is extremely important to pay attention to the units for each of the quantities given. At times, you may be required to convert the unit of speed from km per hr to metre per second or vice versa.

Converting km/hr into m/s

 km = 1000 m = 5 m/s hr 60 x 60 sec 18

Example:
 20 km = 20 x 5 = 5.55 m/sec hr 18

Converting m/s into km/hr:

 m = 18 km/hr s 5

Example:
 20 m = 20 x 18 = 72 km/hr s 5

- To convert minutes into seconds, multiply by 60
- To convert hours into seconds, multiply by 60 x 60

Question Variety

Basically there are 4 types of questions that are asked from this chapter. Understanding and practicing each of the 4 types will help you deal successfully with the problems from this chapter.

Type 1: Calculate either time, speed or distance from the other two given parameters.

Examples:

Q 1. How many seconds does Puja take to cover a distance of 500 m, if she runs at a speed of 30 km/hr?

a) 60 sec
b) 82 sec
c) 95 sec
d) 100 sec
View solution

Correct answer: (a)

Hint:

 Time = Distance Speed
We see that the distance is given in metres while the speed is given in km/hr and the answer is asked in seconds.
 So, convert km/hr into m/s by multiplying 5 m/s to the given value of speed. 18

 30 km = 30 x 5 = 75 m/sec hr 18 9
i.e. Place these values in the formula:
 Time = 500 x 9 = 60 sec 75

Q 2. A cyclist covers a distance of 800 meter in 4 minutes 20 seconds. What is the speed in km/hr of the cyclist?

a) 6.2 km/h
b) 8.4 km/hr
c) 11.05 km/hr
d) 16.07 km/hr
View solution

Correct answer: (c)

 Speed = Distance Time
Hint: Convert minutes into seconds
Time=4 min 20 sec =260 sec
 Speed = 800 = 3.07 m/sec 260

Convert the speed from m/s to km/hr by multiplying with (5/18)
 3.07 x 18 km/hr = 11.05 km/hr 5

Q 3. A man walking at the rate of 6 km/hr crosses a bridge in 15 minutes. The length of the bridge is ______.

a. 1000 m
b. 1250 m
c. 1500 m
d. 1800 m
View solution

Correct answer: (c)

Hint: To find the answer in meter, we will first convert distance from km/hour to meter/sec by multiplying it with 5/18 .Also, change 15 minutes to seconds by multiplying it with 60.

Distance = Speed x Time

1. Convert speed into m/sec:

 6 x 5 m/s = 1.66 m/s 18

2. Convert time from minutes into seconds = 15 x 60 s = 900 sec

3. Calculate : Distance = 1.66 x 900 = 1500 m

Type 2: Calculate speed of two people moving between two points, A and B, in opposite directions & crossing each other on the way.

Examples:

Q 4. Two girls move in opposite directions, one from A to B and other from B to A. The girl from A reaches the destination in 16 hrs and girl from B reaches her destination in 25 hrs, after having met. If former's speed is 25 km/hr, what will be the speed of latter?

a) 10 km/hr
b) 12 km/hr
c) 16 km/hr
d) 20 km/hr
View solution

Correct answer: (d)

Hint: If two bodies A and B move from each other's starting point in opposite directions, they reach their destinations after having met, then their speeds Sa & Sb are given by,

 Sa = tb Sb ta

where t is the time taken by them to cover the distance.
 Sb (25 x 4) = 20 km/hr 5

Q 5. Two buses start at the same time, one from P to Q and the other from Q to P. If both buses reach after 4 hours and 16 hours at Q and P respectively after they cross each other, what would be the ratio of speeds of the bus starting from P and that of the one starting from point Q?

a. 2 : 1
b. 1 : 2
c. 2 : 2
d. 1 : 4
View solution

Correct Option: (a)

Hint:

 SP = tQ SQ tP

SP and SQ are speeds of two the buses at points P and Q respectively.
tP = 18 hrs and tQ = 4 hrs
 SP = 16 SQ 4

 Therefore, ratio of speeds Sp = 4 = 2 SQ 2 1

One bus travels at a speed twice of the other bus.

Type 3: Finding Relative Speed for two bodies moving in same or opposite directions.

Examples:

Q 6. Two towns P & Q are 275 km apart. A motorcycle rider starts from P towards Q at 8 a.m. at the speed of 25 km/hr. Another rider starts from Q towards P at 9 a.m. at the speed of 20 km/hr. Find at what time they will cross each other?

a. 2.45 p.m.
b. 2.30 p.m.
c. 1.35 p.m.
d. 1.15 p.m.
View solution

Correct answer: (b)

Hint: We have read, relative speed between two bodies moving in opposite direction: SR = S1 + S2

Assume, distance traveled by P in x hrs = 25 x km -----(1)
distance traveled by Q in (x-1) hrs = 20 (x-1) km -----(2)

Adding (1) & (2),

25 x + 20 (x -1) = 275

x = 6.5 hrs

(x -1) = (6.5 -1) = 5.5 hrs

Time at which they cross each other = 9 a.m. + 5.5hrs = 2.30 p.m.

The two motorcycle riders cross each other at 2.30 p.m.

Type 4: Numericals on Average Speed when the same part of total distance is traveled at two or more different speeds.

Examples:

Q 7. An aeroplane flying 1000 km covers the first 200 km at the rate of 200 km/hr, the second 200 km at 400 km/hr, the third 200 km at 600 km / hr & last 200 km at the rate of 800 km/hr. Determine the average speed of the aeroplane.

a. 250 km/hr
b. 300 km/hr
c. 480 km/hr
d. 600 km/hr
View solution

Correct answer: (c)

Hint: We know that,

 Time = Distance Speed

 Total time taken = 200 + 200 + 200 + 200 = 25 200 400 600 800 12

 Average speed = 1000 x 12 = 480 km/hr 25

Q 8. Jennifer travels first 4 hours of her journey at a speed of 80 miles/hr and the remaining distance in 6 hours at a speed of 30 miles/hr. What is her average speed in miles/hr?

a. 50 miles / hr
b. 60 miles / hr
c. 75 miles / hr
d. 92 miles / hr
View solution

Correct answer (a)

Hint : If time and speed are given then the average speed is calculated by considering the total distance covered and the total time required.

i.e. Average speed = Total distance / Time

Distance =Time x Speed

Total distance covered by Jennifer = Distance covered in first 4 hours + distance covered in next 6 hours

= (80 x 4) + (30 x 6)

= 500 miles / hr

Total time taken to complete the journey = 4 + 6 = 10 hrs

Therefore,

 Average Speed = Total Distance Time

= 500 / 10

= 50 miles/hr

Practice questions on Time & Distance
Time and Work - Aptitude test, questions, shortcuts, solved example videos
Time and Work - Quantitative aptitude tutorial with easy tricks, tips, short cuts explaining the concepts. Online aptitude preparation material with practice question bank, examples, solutions and explanations. Video lectures to prepare quantitative aptitude for placement tests and competitive exams like MBA, Bank exams, RBI, IBPS, SSC, SBI, RRB, Railway, LIC, MAT. Very useful for freshers, engineers, software developers taking entrance exams. Learn and take practice tests!
Simple Interest - Aptitude test, questions, shortcuts, solved example videos
Simple Interest - Quantitative aptitude tutorial with easy tricks, tips, short cuts explaining the concepts. Online aptitude preparation material with practice question bank, examples, solutions and explanations. Video lectures to prepare quantitative aptitude for placement tests and competitive exams like MBA, Bank exams, RBI, IBPS, SSC, SBI, RRB, Railway, LIC, MAT. Very useful for freshers, engineers, software developers taking entrance exams. Learn and take practice tests!
Problems on Percentage - Aptitude test, questions, shortcuts, solved example videos
Problems on Percentage - Quantitative aptitude tutorial with easy tricks, tips, short cuts explaining the concepts. Online aptitude preparation material with practice question bank, examples, solutions and explanations. Video lectures to prepare quantitative aptitude for placement tests and competitive exams like MBA, Bank exams, RBI, IBPS, SSC, SBI, RRB, Railway, LIC, MAT. Very useful for freshers, engineers, software developers taking entrance exams. Learn and take practice tests!
Post your comment
 Discussion Board Math problem answer is 3300secs vighnu 05-8-2021 math problem solution Shrikanth your solution is wrong . In the first step 2*60*60+45*60=9900 Vighnu 05-8-2021 math problem reply 2 hours 45 minutes = 2*60*60+45*60=5100sec4km/hr = 4 * (5/18) = (10/9)m/sDistance covered in first case = (10/9) * 5100 = (51000/9)metersnow calculate time for same distance ,but speed is different,12km/hrs12km/hrs = 12* (5/18)m/secTime = Distance / Speed = (51000/9) / (60/18) = 1700 sec shrikant 06-23-2020 averages there shoud be a correction in 5th ques it should be 16/4 i.e. 4:1. Aman 01-19-2020 reply 48KM Rama 07-18-2016 average time if 4 persons spends between 1 to 20 minute?s6 persons spends 21 to 30 minutes8 persons spends 31 to 40 minutes to access water, what will be the average time spent. Enoch 07-5-2016 Aptitude - Time and Distance A coach travels over a hilly route from town A in the highlands to town B by the coast. Going uphill it travels at 42 mph, going downhill it travels at 56 mph and on level ground it travels at 48 mph. It takes 2 hours and 20 minutes to travel from A to B and 2 hours and 40 minutes to travel back. Find the distance between A and B. Nats 09-18-2015 speed time distance Ans. 160km / hr meenakshi 05-5-2015