A. 700

B. 350

C. 1000

D. 4200

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**ANSWER: A. 700Solution: A boat travels at the speed of 14 km/hr in still water. => Speed of stream = 1.2 kmph=> Speed of boat downstream becomes 14 + 1.2 = 15.2 kmph=> Speed of boat upstream becomes 14 - 1.2 = 12.8 kmphTotal time taken in the journey = Journey downstream + Journey upstreamTherefore, 4864(1/12.8 + 1/15.2) = 700 hours **

A. 159

B. 209

C. 201

D. 212

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**ANSWER: B. 209Solution: This solution can be determined by 2 ways. Include at least one boy in each group and make 4 cases. A simpler way would be finding out total ways of selecting 4 people from the total group and subtracting the case with no boy.=> Group of 4 out of 10 children - Group of 4 out of 4 girls. => 10C4 - 4C4=> 210 - 1 => 209 **

A. 4% of A

B. 10% of A

C. 20% of A

D. None

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**ANSWER: A. 4% of ASolution: It is given that B measures 20% of A => So, 20% of A = B or 20/100 * A = B - (1)B% of 20= B/100 X 20= 2B/10 ---(2)=> Now, B% of 20Substituting (1) in (2) we get2*(2A/10) / 10= 4A/100 Hence, B% of 20 = 4% of A**

A. 1:3

B. 2:1

C. 1:3

D. 3:1

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**ANSWER: B. 2:1Solution: Let us consider the relationships here:Time and Profit ---------------Direct Relationship ---- More time More profitInvestment & Profit ------Direct Relationship ---- More investment More profitRatio of profit = Investment * Time of Investment= 45000 * 12 : 30000 * 9= 2:1**

A. 28L

B. 29L

C. 29.16L

D. 28.4L

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**ANSWER: C. 29.16LSolution: In regard to the problem let after n times liquid in the container is x and liquid removed is y =>Liquid in container= x=>Liquid removed= yAfter one trial, quantity of pure liquid= x- (1-y/x)After n trials quantity of pure liquid = x - (1 -y/x)nTherefore, Putting the values ( x = 40L y = 4L N=3) and solving => 40- (1-4/40)3= 29.16L**

A. 15

B. 18

C. 16

D. 20

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**ANSWER: C. 16Solution: According to the question let n be the number of articles. => Cost price of n articles = n=> Selling price of n articles = 20=> Profit % = 25%=> Profit % = (SP - CP)/CP X 100 Putting the values in the formula(20-n)/n x 100 = 25=> 5n/4 = 20=> n = 16**

A. 7/8

B. 1/8

C. 2/8

4. 4/8

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**ANSWER: A. 7/8Solution: It is given that 3 coins are tossed simultaneously.=>Total outcomes when one coin is tossed=2=>Total outcomes when 3 coins are tossed= 2**

A. 6 hours

B. 8 hours

C. 9 hours

D. 10 hours

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**ANSWER: B. 8 hoursSolution: It is given that tank is filled in 2 hours. Let tank drain out in y hours=> Part of the tank filled in one hour = 1/2=> Part emptied in one hour by leak = 1/y=>Part filled in one hour following leak = 1/ (8/3)In one hour: 1/2 - 1/7 = 3/8 Therefore, Solving for y, y=8**

A. 26m

B. 32m

C. 24m

D. 28m

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**ANSWER: B. 32mSolution: This is a simple speed time problem. Given conditions: =>Speed of P= 224/28 = 8m/s=>Speed of Q=224/32 = 7m/s=>Difference in time taken = 4 secondsTherefore, Distance covered by P in that time= 8m/s x 4 seconds = 32 metres**

**RE: Aptitude model placement papers with solution - set 2 -kavitha mangali (01/26/21)**- very nice questions but i want brief explanation
**RE: Aptitude model placement papers with solution - set 2 -kavitha mangali (01/26/21)**- very nice questions but i want brief explanation
**RE: Aptitude model placement papers with solution - set 2 -kavitha mangali (01/26/21)**- very nice questions but i want brief explanation
**RE: Aptitude model placement papers with solution - set 2 -aswini (02/02/17)**- please give 10th question
**RE: Aptitude model placement papers with solution - set 2 -shatakshi (08/10/15)**- very nice quistions

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