Aptitude model placement papers with solution - set 2Q1. A boat has a speed of 14kmph in standing water. The stream has a speed of 1.2kmph. What time does the boat take to go to a distance of 4864 km and come back? (hours)
D. 4200View Answer / Hide Answer
Q2. In how many different ways can a group of 4 be made out of 4 girls and 6 boys such that at least one boy is selected each time?
ANSWER: A. 700
Solution: A boat travels at the speed of 14 km/hr in still water.
=> Speed of stream = 1.2 kmph
=> Speed of boat downstream becomes 14 + 1.2 = 15.2 kmph
=> Speed of boat upstream becomes 14 - 1.2 = 12.8 kmph
Total time taken in the journey = Journey downstream + Journey upstream
Therefore, 4864(1/12.8 + 1/15.2) = 700 hours
D. 212View Answer / Hide Answer
Q3. 20% of A is B, then B% of 20 is same as what?
ANSWER: B. 209
Solution: This solution can be determined by 2 ways. Include at least one boy in each group and make 4 cases. A simpler way would be finding out total ways of selecting 4 people from the total group and subtracting the case with no boy.
=> Group of 4 out of 10 children - Group of 4 out of 4 girls.
=> 10C4 - 4C4
=> 210 - 1
A. 4% of A
B. 10% of A
C. 20% of A
D. NoneView Answer / Hide Answer
Q4. With an investment of 45000, X starts a business which is joined by Y after 3 months with 30000. How should they share the profit at the end of the year?
ANSWER: A. 4% of A
Solution: It is given that B measures 20% of A
=> So, 20% of A = B or 20/100 * A = B - (1)
B% of 20= B/100 X 20= 2B/10 ---(2)
=> Now, B% of 20
Substituting (1) in (2) we get
2*(2A/10) / 10= 4A/100
Hence, B% of 20 = 4% of A
D. 3:1View Answer / Hide Answer
Q5. A container has 40L milk. 4L milk is taken out and replaced with water, the process done three times. What is the amount of milk now left?
ANSWER: B. 2:1
Solution: Let us consider the relationships here:
Time and Profit ---------------Direct Relationship ---- More time More profit
Investment & Profit ------Direct Relationship ---- More investment More profit
Ratio of profit = Investment * Time of Investment
= 45000 * 12 : 30000 * 9
D. 28.4LView Answer / Hide Answer
Q6. The cost price of a particular amount of articles is same as the number of articles. Selling price of the articles comes out to be 20. Over the whole transaction 25% is gained. What is X?
ANSWER: C. 29.16L
Solution: In regard to the problem let after n times liquid in the container is x and liquid removed is y
=>Liquid in container= x
=>Liquid removed= y
After one trial, quantity of pure liquid= x- (1-y/x)
After n trials quantity of pure liquid = x - (1 -y/x)n
Therefore, Putting the values ( x = 40L y = 4L N=3) and solving
=> 40- (1-4/40)3
D. 20View Answer / Hide Answer
Q7. Three coins are tossed. What is the probability of getting at most two tails?
ANSWER: C. 16
Solution: According to the question let n be the number of articles.
=> Cost price of n articles = n
=> Selling price of n articles = 20
=> Profit % = 25%
=> Profit % = (SP - CP)/CP X 100
Putting the values in the formula
(20-n)/n x 100 = 25
=> 5n/4 = 20
=> n = 16
4. 4/8View Answer / Hide Answer
Q8. A pump fills a tank in 2 hours. Due to a leak it took 2 2/3 hours to fill the tank. In how much time will the leak drain the entire tank?
ANSWER: A. 7/8
Solution: It is given that 3 coins are tossed simultaneously.
=>Total outcomes when one coin is tossed=2
=>Total outcomes when 3 coins are tossed= 2n = 2 X 2 X 2
Favourable outcomes: TTH, THT, HTT, THH, THT,HHT,HHH=7
Therefore, Probability= 7/8
A. 6 hours
B. 8 hours
C. 9 hours
D. 10 hoursView Answer / Hide Answer
Q9. For a race a distance of 224 meters can be covered by P in 28 seconds and Q in 32 seconds. By what distance does P defeat Q eventually?
ANSWER: B. 8 hours
Solution: It is given that tank is filled in 2 hours. Let tank drain out in y hours
=> Part of the tank filled in one hour = 1/2
=> Part emptied in one hour by leak = 1/y
=>Part filled in one hour following leak = 1/ (8/3)
In one hour: 1/2 - 1/7 = 3/8
Therefore, Solving for y, y=8
D. 28mView Answer / Hide Answer
ANSWER: B. 32m
Solution: This is a simple speed time problem. Given conditions:
=>Speed of P= 224/28 = 8m/s
=>Speed of Q=224/32 = 7m/s
=>Difference in time taken = 4 seconds
Therefore, Distance covered by P in that time= 8m/s x 4 seconds = 32 metres