Aptitude model placement papers with solution - set 4Q1. A man walks with 3kmph speed in the direction of a train. How much time will a 500m long train take to overtake him at a speed of 63kmph?
A. 42 seconds
B. 30 seconds
C. 50 seconds
D. 36 secondsView Answer / Hide Answer
Q2. Arnesh is thrice as good as Bhanu in a work. He finishes a work in 60 days less than that taken by Bhanu. How many days will they take to complete the work together?
ANSWER: B. 30 seconds
Distance to be covered = 500 metres
Effective speed will be equal to difference in the speed of ma and train as they move in opposite directions.
Thus, effective speed = 63kmph-3kmph= 60kmph.
60kmph is equal to 50/3 m/s.
Time = Distance/ Speed
Thus, time taken will be equal to 500/(50/3).
On solving, time = 30 seconds.
Therefore, the train will take 30 seconds to overtake the man.
A. 18 days
B. 15 days
C. 22.5 days
D. 16 daysView Answer / Hide Answer
Q3. Find the ratio of speed of truck to train if truck covers 550m in 1 minute and train covers 33 km in 45 min.
ANSWER: C. 22.5 days
Let us assume that Arnesh finishes his work in 1 day. According to the question, Bhanu will take 3 days to finish the same work. Therefore, there is a difference of two days between the two if Bhanu finishes the work in 3 days.
If the difference is 60 days, then Bhanu will take 3/2 * 60 days, that is 90 days.
Amount of work Bhanu does in 1 day = 1/90
Amount of work Arnesh does in one day is thrice that of Bhanu, that is 3*(1/90)
Amount of work they do together is in one day is 1/90 + 1/30 = 2/45.
Thus, they take total 45/2 days to complete the entire work.
Therefore the answer is 22.5 days.
D. 1:2View Answer / Hide Answer
Q4. What investment must be made to obtain Rs 650 income from 10% stock at Rs 96?
ANSWER: B. 3:4
Using the formula, speed=distance/time
Speed of truck = 550/60 m/s
Speed of train= 33000/(45*60) m/s
Ratio of speed of truck to train= (550/60 ) / [33000/(45*60)]
Hence, the ratio is 3:4
D. 3500View Answer / Hide Answer
Q5. 60 apples and 75 oranges together cost Rs 1320. Cost of 80 apples is equal to that of 120 oranges. What will b the price of 25 apples and 40 oranges?
ANSWER: B. 6240
Given market value = Rs 96
Required income = Rs 650
We assume the face value to be Rs 100.
To obtain 10% of face value, investment had to be Rs 96. So, in order to receive Rs 650, required investment is:
Thus the investment should be Rs 6240.
D. 780View Answer / Hide Answer
Q6. An amount on simple interest over 8 years earns 80% increase. At the same rate, what will be the compound interest on a sum of Rs 14000 in 3 years?
ANSWER: B. 620
Let price of one apple be A and price of one orange be B.
According to question, 80A=120B
B=2A/3 equation 1
Price of 60 apples and 75 oranges is Rs 1320.
This can be represented as 60A+75B=1320
Substituting for B from equation 1, 4A+5 (2A/3) =88
diving both sides by 2,
diving both sides by 11,
B= 2A/3, B= 8
Total price of 25 apples and 40 oranges= 25A+40B
That is 25*12+40*8, solving, 300+320
Thus the total price is Rs 620.
D. 3714View Answer / Hide Answer
Q7. What time will be taken by an amount of Rs. 900 to yield Rs. 81 as interest at 4.5% per annum of simple interest?
ANSWER: B. 4636
Let the amount be Rs 100.
Simple interest is Rs 80 as the 80% increase is due to simple interest.
Rate of interest= 100 * SI%* time
Solving, rate= 100*80%*8= 10% per annum
Compound interest on a sum of Rs 14000 after 3 years ar 10% rate :
Amount = P(1+rate*100) * time
= 14000 (1*10%)*3
Therefore, the compound interest is Rs 4636.
A. 2 years
B. 1 years
C. 3 years
D. 4 yearsView Answer / Hide Answer
Q8. Find the value of x if:
ANSWER: A. 2 years
P= Rs 900
Rate = 4.5*
SI= Rs 81
=> SI= Time*P*rate
calculating for rate,
=> Time= SI/rate*P
=> 2 years
Thus, it will take 2 years to yield Rs 81.
5 + log10
(5x + 1) = log10
(x + 5) + 1
D. 5View Answer / Hide Answer
Q9. Which is the odd number?
ANSWER: B. 3
Solution: To solve this problem a logarithmic identity needs to be kept in mind:
i.e. logax + logay = logaxy
=> log105 + log10 (5x + 1) = log10 (x + 5) + 1 can be written as:
=> log10 (5(5x + 1)) = log10 (10(x +5)) (Taking 1 = log1010)
=> log (25x + 5) = log (10x + 50)
Taking antilog both sides:
5(5x + 1) = 10(x + 5)
=> 5x + 1 = x + 5
=> 3x = 9
=> x = 3
1, 8, 27, 64, 125, 196, 216, 343
D. 1View Answer / Hide Answer
Q10. 2 students gave an examination. One of them scored 9 marks more than other and his marks were 56% of the sum of total of both their marks. What are their individual marks?
ANSWER: B. 196
The pattern in the given question is 13, 23,,33...
In the series, 196 is not a perfect cube and therefore the odd number.
D. 44,36View Answer / Hide Answer
ANSWER: A. 42,33
Let marks of one of the students be X.
The marks of the other will be X+9
According to question, X+9 = 56% of X+ (X+9)
Solving, X + 9 = 56/100* (2X + 9)
=> 25X + 225 = 28X + 126
=> 3X = 99
=> X = 33
Marks of one are 33, while of the other are 33+9 = 42.