A. 48

B. 42

C. 28

D. 36

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**ANSWER: B. 42Solution: First, we find out the number of times a particular letter occurs in the given word:2 – I1 – A 1 – D1 – N=> Total number of solutions minus the number of times all three vowels are together. Now, using the concept of permutation and combination:=> Divide the possible combination by 2! because it occurs twice and replacing one by another will cause no difference in the word. => Total number of words that can be formed: 5!/2! => Total number of words that can be formed keeping all the vowels together: 3! 3!/2! => 60 – 18 = 42 **

A. 1/50

B. 3/25

C. 21/46

D. 25/122

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**ANSWER: C. 21/46 Solution: It is given that 3 students are to be selected randomly from a group of 25 students. => Total number of outcomes: **

A. 15

B. 12

C. 10

D. 20

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**ANSWER: C. 10 Solution: It is given that sum of two numbers is 100. Let the two numbers be x and 100 – x and HCF is 5 and LCM is 495=> We need to apply the formula: HCF x LCM = Product of two numbersWhich gives x(100 – x) = 495 x 5Solving the equation we get a quadratic which looks like this:x**

A. 9240

B. 9064

C. 9184

D. 9152

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**ANSWER: A. 9240 Solution: These types of questions are to be solved by trial and error. Make sure minimum amount of time is wasted and your calculations are quick. Devote maximum 1 minute to such questions. Here in this case clearly 9240 is the closest number which divides 88. **

2*3 = √13

3*4=5

Find the value of 5*12.

A. √29

b. √19

C. 13

D. 7

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**ANSWER: C. 13 Solution: The code "*" does not represent multiplication here. It represents the pythagoras code where the two numbers operated upon represent length and breadth of a right angled triangle.=> 2 * 3 =√(2**

A. 25

B. 30

C. 20

D. 22

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**ANSWER: C. 20 Solution: All the data given in the question points to the equation mentioned below:Considering the three numbers to be a,b and c:(a+b+c)**

Determine the value of y.

A. xz/(x+z)

B. xz/2(z-x)

C. 2xz/(x+z)

D. xz/2(x-z)

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**ANSWER: C. 2xz/(x+z) Solution: This is one of the tougher questions:Let a**

A. 80%

B. 75%

C. 78.66%

D. 71.25%

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**ANSWER: A. 80% Solution: One of the most basic questions. Let income of B be 100. Income of A is 25% more than income of B which means Income of A becomes 125Now income of B in terms of A = 100/125 *100 = 80%**

A. x + y

B. x – y

C. x – y/(x + y)

D. 1

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**ANSWER: C. x – y/(x + y) Solution: A simple problem involving geometric progression (G.P) In each term, a term of (x + y) is divided. Hence the third term becomes x-y/(x+y)**

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