A. 42

B. 46

C. 48

D. 38

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**ANSWER: A. 42 Solution: 1 man is equivalent to 2 boys in work capacity. 12 men + 18 boys = 12 x 2 + 18 = 42 boys.Let the required number of boys be x. So Total number of people doing work = 21 men x 2 (according to work capacity) + x boys.Taking respective ratios as required:Given:=> Hours 50:60=> Minutes per hour 9: 15/2=> Work 1:2=> People: 42: 42 + x=> 50 x 9 x 1 x (42+x) = 60 x 15/2 x 2 x 42 => 42 +x = 84x = 42**

A. 10 minutes

B. 15 minutes

C. 12 minutes

D. 9 minutes

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**ANSWER: D. 9 minutes Solution: Let B be turned off after X minutes. Part of water will be filled by A + B in x minutes + After tap B is closed rest filled by A in (30-x) minutes = 1=> x/(time taken to fill the container by each separately) + 30 - x/(time taken to fill the container by A alone) = 1=> x(2/75 + 1/45) + (30-x)2/75 = 1=> 11x + 180 – 6x = 225 Therefore, x = 9 minutes**

A. 26.2 km

B. 25.7 km

C. 23.2 km

D. 26.67 km

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**ANSWER: D. 26.67 km Solution: Distance travelled by each of them is to be made equal.=> Distance travelled walking = Distance covered cycling.Let after 4 hours of walking, A walk for x hours more before B catches up with him.=> Distance = Speed * Time(4+x)4 = 10xx = 8/3Therefore, It takes B 8/3 hours to catch up with A. Distance: 8/3 x 10 = 80/3 km = 26.67 **

A. 2 kmph

B. 5 kmph

C. 4 kmph

D. 3 kmph

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**ANSWER: C. 4 kmph Solution: Simple Division. No stream current mentioned. Trick question. Speed= Distance/Time. Speed= 3/4 km / (11.25/60) hrTherefore, Speed = 4 km/hr**

A. Rs 7500

B. Rs 6600

C. Rs 4500

D. Rs 3000

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**ANSWER: B. Rs 6600 Solution: Let initial amount that the man invests be ALet x be the capital=> Profit on 1st investment + Profit on 2nd investment + Profit on 3rd investment => S.I. = P X R X T=> Remainder of capital = 1 - 1/3 - 1/4 = 5/12x (x being the capital)=> a*1/3 *7/100 + 1/4 *a * 8/100 + 5x/12*a* 10/100 = 561Therefore, a = 6600**

A. Rs 9040

B. Rs 8900

C. Rs 8920

D. Rs 9160

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**ANSWER: C. Rs 8920 Solution: Use the formula Amount = Principal Amount(1 + R/100)**

A. S < T < C

B. T < S < C

C. C < S < T

D. T < C < S

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**ANSWER: B. T**

Solution: Let a be the side of square b be the side of triangle and r be the radius of the circle:

It is given that perimeter of all the three figures is same

=> 4a = 3b = 2πr

=> a = 3b/4

=> r= 3b/2π

Areas: Now that we have all the three sides in terms of b we can equate and compare areas of the three equations:

Square: 9b

Triangle: b

Circle: 9b

From this we can say that Area (Circle) > Area (Square) > Area (Triangle)

A. 12%

B. 12.36%

C. 12.64%

D. 6%

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**ANSWER: B. 12.36% Solution: Let old radius be 1rAs the radius has increased by 6%, the new radius = 1.06 rNew area = π (1.06r)**

A. 4.7

B. 4.8

C. 4.3

D. 4.6

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**ANSWER: D. 4.6 Solution: In the given question we have taken average of 6 numbers taken 2 at a time which makes 3 numbers.=> 3.95 (Average of 1st and 2nd number) => 3.85 (Average of 3rd and 4th number)=> 3.4 (Average of 5th and 6th number)3.95 = (3.4 + 3.85 + x)/3x = 4.6 **

15, 16, 34, 105, 424, 2124

A. 105

B. 424

C. 34

D. 2124

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**ANSWER: D. 2124 Solution: The following pattern has been followed in this question:16 = 15 x 1 + 134 = 16 x 2 + 2We have established that previous number is multiplied by increasing numbers (1,2,3,4.....) and then added by increasing numbers (1,2,3,4...)105 = 34 x 3 + 3424 = 105 x 4 + 42125 = 424 x 5 + 5=> 2124 is incorrect**

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