Aptitude model placement papers with solution - set 7Q1. What is the angle between the hour and minute hand at 3:40?
D. 125View Answer / Hide Answer
Q2. 15th august 2010 was which day of the week?
ANSWER: B. 130
When minute hand is behind the hour hand, the angle between the minute hand and hour hand at M minutes past H hours is given by:
=> 30 * (H-M/5) + M/2
When minute hand is ahead of hour hand, the formula becomes:
=> 30* (M/5-H) – M/2
Applying the second formula as here the minutes hand is ahead of the hour hand.
=> 30* (40/5-3) – 40/2
=> 30* (8-3) – 20
=> 30*5 – 20
Thus the angle formed is 130 degrees.
D. FridayView Answer / Hide Answer
Q3. A boatman rows 96 km downstream in 8 hours with a stream speed of 4kmph. How much time will he take to cover 8km upstream?
ANSWER: B. Sunday
15th August 2010 can be written as 2009 + days from 1st January 2010 to 15th August 2010.
=> Total number of odd days in 400 years = 0
Hence, total number of odd days in 2000 years = 0 (as 2000 is a perfect multiple of 400)
Odd in days in the period 2001-2009:
7 normal years + 2 leap yeas
=> (7*1) + (2*2) = 11
=> Odd days will be 11- (7*1) = 4
Days from January 1 to August 15 in 2010: 31+28+31+30+31+30+31+15
= 227 days.
= 32 weeks and 3 days, this gives additional 3 odd days.
=> Total odd days= 3+4=7
=> 7 odd days=1 week= 0 odd days
=> 0 odd days= Sunday
Thus, 15th August 2010 was a Sunday.
A. 4 hours
B. 6 hour
C. 2 hours
D. 1 hoursView Answer / Hide Answer
Q4. What is the true discount if a banker’s discount on a bill due 4 months hence is 420 at 15%?
ANSWER: C. 2 hours
Speed = distance/time
Speed downstream: 96 / 8 km/hr = 12kmph
Speed of stream = 4kmph
Effective speed of boat = (12-4) kmph
Distance to be travelled upstream= 8 km
Speed upstream = boat speed-current speed
= 8-4 kmph
= 4 kmph
Time taken = distance/speed = 8/ 4 hours
Thus it will take 2 hours to go upstream.
D. 380View Answer / Hide Answer
Q5. India has a run rate of 3.2 in the first 10 overs. What should be the run rate in remaining 40 overs to win a game of 282 runs?
ANSWER: A. 400
Using the formula:
True Discount = (Banker’s Discount * 100 * 100)+ Total Rate
=> True Discount = 420*100/100+15
Thus the true discount is Rs 100.
D. 8View Answer / Hide Answer
Q6. While calculating the edge of a square, a worker makes an error of 2% in excess. What % error does he make in calculating area? (%)
ANSWER: A. 6.25
Runs scored in first 10 overs:
=> Rate*Overs= 3.2*10 = 32 runs
=> Required runs = 282-32 = 250
=> Left overs= 40
Required rate = runs/overs
=> 6.25 runs per over is needed to win the game.
D. 4.004View Answer / Hide Answer
Q7. The sum of ages of 5 children born at three year interval each is 50. How old is the youngest child?
ANSWER: A. 4.04
Given Error = 2% while measuring the side of a square.
If the correct value of the side of square is 100, the measured value:
=> 100 + 2% *100
The area of square with edge 100 = side*side
The area of square with side 102 = 102*102= 10404
Error in area calculation = 10404-1000 = 404
% error= (404/10000)*100
D. 3View Answer / Hide Answer
Q8. A pipe is 30 m long and is 45% longer than another pipe. Find the length of the other pipe.
ANSWER: C. 4
Let the age of youngest child be X
According to the question,
X + (X+3) + (X+6) + (X+9) + (X+12) = 50
5X + 30= 50
5X = 50-30
5X = 20
X = 20/5 = 4
Age of youngest child is 4 years.
D. 20.5View Answer / Hide Answer
Q9. A man cycles at a rate of 4kmph. He cycles for 45 minutes and then takes a 15 minute break. Determine the total time taken to cover 12 kms by him.
ANSWER: A. 20.68
Let length of other pipe be X
According to question,
30 = 45/100 X + X
30 = 0.45X + X
30 = 1.45 X
X = 20.68m
Thus the length of the other pipe is 20.68 metres.
A. 4 hours 35 minutes
B. 4 hours
C. 3 hours
D. 3 hours 45 minutes View Answer / Hide Answer
Q10. In a race, A beats B by 15 metres and C by 29 metres. If B and C run over the course together, B wins by 15 metres. What is the length of the course?
ANSWER: D. 3 hours 45 minutes
Speed of man = 4kmph
Time for which he cycled = 45 minutes.
Distance covered = speed*time
Total time to cover 3 km = 45 minutes + 15 minutes = 60 minutes = 1 hour
Thus 3 km is covered in 1 hour
Required distance to be covered = 12 km
Beginning from origin point, he covers 9 km in 3 hours taking 15 minutes rest after every 45 minutes. To complete 12 kms he goes another 3 km in 45 minutes.
Thus, total time he takes is 3 hours 45 minutes.
D. 160mView Answer / Hide Answer
ANSWER: A. 225m
Let X be the length of the course
according to the question,
A beats B by 15 metres and C by 29 metres
If A runs X metres, B runs (X-15) and C runs ( X-29) metres.
B and C together run, B runs X metres and C runs (X-15)
=> If B runs 1 metre, C runs X-15/X
=> B runs X-15 m, C runs (X-15/x) * (X-15)
X-29 = (X-15)(X-15) / X
X2 -29X= X2 – 30 X + 225
X = 225
Thus, length of the course is 225 metres.