# Calculation of power dissipation in FM wave

## For a FM signal v(t) = 20 cos ( 10* 10^{8}t + 30 sin 3000t), calculate the power dissipated by the FM wave in a 20Ω resistor.

**Options:**

a) 100 Watts

b) 10 Watts

c) 200 Watts

d) 20 Watts

Correct Answer: b) 10 Watts

**Explanation:**

Standard expression for FM signal is given by

v(t) = A cos ( Ω_{c}t + m_{f} sin Ω_{m}t)

Comparing with the given equation,

A= 20

The dissipated power is given by P= V^{2}_{rms}/R

= (20/√2)^{2}/ 20

= 10Watts

#### Discussion

**RE: Calculation of power dissipation in FM wave -Vrindha (06/19/20)**- power of fm modulated signal , 15cos(2p * 1000000t +5sin2p * 1000t)