Hydro Power - MCQs with answers

Hydro Power - MCQs with answers


Q1. The electrical power developed by a hydroelectric plant is given by ______________.

a. P = (735.5 / 75) Q H η kW
b. P = (75/735.5) Q H η kW
c. P = (75 * 735.5) Q H η kW
d. P = 7 / (75 * 735.5) Q H η kW

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ANSWER: a. P = (735.5 / 75) Q H η kW

Explanation: When water drops through a height, its energy is able to rotate the turbine wheels which are coupled to the alternators. The power developed is P = (735.5 / 75) Q H η kW.

Where, Q = water discharge m3/sec, H = water head in Metres η = overall efficiency of the turbine alternator



Q2. In a hydro plant, if the discharge is 200 m3/s and the head of the water is 100 m. If the efficiency of the turbine alternator is set to 0.85, find the power developed

a. 66.67 MW
b. 166.7 MW
c. 667.8 MW
d. 176.52 MW

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ANSWER: b. 166.7 MW

Explanation: P = (735.5 / 75) Q H η kW

Q = 200 m3/s,

H = 100 m, and η = 0.85

P = (735.5/75) * 200 *100 *0.85

= 166.713 *103 kW

= 166.713 MW


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