# Model Aptitude questions and answers for placement - Set 4

1)   A, B and C enter into partnership. A invests 3 times as much as B invests and B invests two third of what C invests. At the end of the year, the profit earned is Rs. 8500. What is the share of B?

a. Rs. 1245.50
b. Rs. 1623.53
c. Rs. 1545.45
d. Rs. 1145.15
 Answer  Explanation ANSWER: Rs. 1545.45 Explanation: Let C's capital = Rs. y. Then, B's capital = Rs. (2/3)yA's capital = Rs. (3 × (2/3)y) = Rs. 2yTherefore, ratio of their capitals = 2y : (2/3)y : y = 6 : 2 : 3Hence, B's share = Rs. (8500 x 2/11) = Rs. 1545.45

2)   If 36 men can do a piece of work in 25 hours, in how many hours will 10 men do it?

a. 100 hours
b. 90 hours
c. 60 hours
d. 30 hours
 Answer  Explanation ANSWER: 90 hours Explanation: Let the required numbers of hours be X. Less men, More hours (Indirect proportion)Therefore, 10 : 36 :: 25 : X = (10 x X) = (36 x 25) = X = (36 x 25)/10 = 90.Hence, 10 men can do it in 90 hours.

3)   What is the value of (12 + 22 + 32 + 42  + ----- + 102)

a. 295
b. 324
c. 385
d. 391
 Answer  Explanation ANSWER: 385 Explanation: (12 + 22 + ….. + n2) = (1/6) n(n + 1) (2n + 1) Here, n = 10 Therefore,(12 + 22 + ….. + 102) = (1/6) 10 (10 + 1) ( 2 x 10 + 1) = (1/6) x 10 x 11 x 21 = 385

4)   By purchasing an article at 20 % discount on the original price and then selling it at a price of 25% above the original price, a trader earns Rs. 200 as the profit. What was the original price of the article?

a. Rs. 444.44
b. Rs. 255.50
c. Rs. 100.10
d. Rs. 810
e. None of these
 Answer  Explanation ANSWER: Rs. 444.44 Explanation: Let the original price of the article be Rs. 100. Hence the purchase price for the trader would be Rs. 80 and his selling price would be Rs. 125. Thus, he would earn a profit of Rs. 45 (125 – 80). Therefore, Profit is Rs. 45 if the original price is Rs. 100 Hence, if profit is Rs. 200, then original price will be.. = 100x 200/45 = Rs. 444.44

5)   Shruti purchased several number of three articles P, Q and R in the proportion 3 : 2 : 3. If the unit costs of the articles P, Q and R are 200, Rs. 90 and Rs. 60 respectively, how many articles of Q must have been purchased in the total purchases of Rs. 4800?

a. 8
b. 10
c. 12
d. 14
e. None of these
 Answer  Explanation ANSWER: 10 Explanation: Let the number of articles of types P, Q and R be 3a, 2a and 3a respectively.Thus, we get, (200 x 3a) + (90 x 2a) + (60 x 3a) = 4800960a = 4800a = 5Hence, the number of articles of type “Q” = 2x5 = 10

6)   A train travels a certain distance by taking 3 stops of 20 minutes each. Considering the period of stoppage, the overall speed of the train comes to 40 kmph; while without consideration of stoppage, it is 60 kmph. How much distance must the train have travelled ?

a. 170 kms
b. 120 kms
c. 270 kms
d. None of these
e. Cannot be determined
 Answer  Explanation ANSWER: 120 kms Explanation: Let the time taken to travel the distance without taking stops be “b” hours.Thus, we get,60 x b = 40(b + 1) b = 2Thus, we get 60 x 2 = 120 kms

7)   Rohan was 4 times as old as his son 6 years ago. After 6 years Rohan will be twice as old as his son. What is son's present age?

a. 10 years
b. 12 years
c. 14 years
d. 18 years
 Answer  Explanation ANSWER: 12 years Explanation: Let son's age 6 years ago be X years. Then, Rohan's age 6 years ago = 4X years.Son's age after 6 years = (X + 6) + 6 = (X + 12) yearsRohan's age after 6 years = (4X + 6) + 6 = (4X + 12) yearsTherefore 2(X + 12) = 4X + 122X = 12 X = 6Hence, son's present age = (X + 6) = 12 yearsRohan's present age = (4X + 6) = 30 years

8)   If √10 = 3.16, find the value of If √5/2

a. 1.30
b. 1.58
c. 2.03
d. 2.15

9)   Find the average of first 30 natural numbers.

a. 12
b. 15.5
c. 14.5
d. 16
 Answer  Explanation ANSWER: 15.5 Explanation: Sum of first n natural numbers = n(n+1)/2Hence, sum of first 30 natural numbers = (30 x 31)/2 = 465Therefore, required average of = 465/30 = 15.5

10)   If logxy = 100 and log3x = 10, then the value of y is:

a. 310
b. 3100
c. 31000
d. 310000
 Answer  Explanation ANSWER: 31000 Explanation: log3x = 10 Hence,x= 310logx y = 100 y =x100 = (310)100= y = 31000