Analytical Reasoning Practice Test Questions - Non Verbal Reasoning

The figure may be labelled as shown in the solution image. The horizontal lines are BD, GI, EF, i.e. 3 in number. The vertical lines are DI, BG, AH, i.e. 3 in number. The slanting lines are AB, AD, CG, CI, i.e. 4 in number. Thus, there are 3 + 3 + 4 = 10 straight lines in the figure.

The figure may be labelled as shown in the solution image. The horizontal lines are BF, GI, i.e. 2 in number. The vertical lines are FI, BG, DH, i.e. 3 in number. The slanting lines are BH, DG, DI, FH, AC, AE, i.e. 6 in number. Thus, there are 2 + 3 + 6 = 11 straight lines in the figure.

The figure may be labelled as shown in the solution image. The horizontal lines are AC, DE, HJ, KL, i.e. 4 in number. The vertical lines are DK, EL, FH, BI, GJ, i.e. 5 in number. The slanting lines are AF, BF, BG, CG, FK, HK, GL, JL, i.e. 8 in number. Thus, there are 4 + 5 + 8 = 17 straight lines in the figure.

The figure may be labelled as shown in the solution image. The triangles are: AEG, AEF, AGF, ABD, ABF, ABC, ADF, ADC, EBF, GDF, BDF, BFC, DFC. Thus, there are 13 triangles in the figure.

The figure may be labelled as shown in the solution image. The triangles are: AFI, AFG, AFH, AIG, AIH, AGH, ABE, ABC, ABD, AEC, AED, ACD. Thus, there are 12 triangles in the figure.

The figure may be labelled as shown in the solution image. The triangles are: AHJ, AHI, AJI, AEG, AEI, AEF, AGI, AGF, ABD, ABC, ADC, HEI, JGI, EGI, EIF, GIF. Thus, there are 16 triangles in the figure.

The figure may be labelled as shown in the solution image. The triangles are: ACM, ACK, ACG, AMK, AKG, ABF, ABD, AFD, CMK, CMG, CBH, CBE, CHE, MKG, MHL, MHJ, MLJ, KLF, KLI, KFI. Thus, there are 20 triangles in the figure.

The figure may be labelled as shown in the solution image. The triangles are: ABI, ABH, ABE, AIH, AHE, BIH, BIE, IHE, CDG, CDF, CDE, CGF, CFE, DGF, DGE, GFE. Thus, there are 16 triangles in the figure.

The figure may be labelled as shown in the solution image. The triangles are: ABI, AIG, BED, ICH, ICD, IHD, IHF, IDF, GJH, CEK, CKJ, CHD, CHF, CDF. Thus, there are 14 triangles in the figure.

The figure may be labelled as shown in the solution image. The triangles are: BDH, BDF, BDA, BDE, BHF, BFE, BAC, BAE, BCE, DHF, DHE, DAC, DAE, DCE, HFE, HGE, FGE. Thus, there are 17 triangles in the figure.

The figure may be labelled as shown in the solution image. The triangles are: BLC, FNE, NLA, NAM, NKJ, LAM, LGH, ACE, ACD, AED, AHJ, AHI, AJI. Thus, there are 13 triangles in the figure.

The figure may be labelled as shown in the solution image. The triangles are: BGC, FIE, LJH, LIH, LKH, JGH, JKH, AGI, AGH, AIH, ACE, ACD, AED. Thus, there are 13 triangles in the figure.

The figure may be labelled as shown in the solution image. The horizontal lines are BC, DE, FI, i.e. 3 in number. The slanting lines are AF, AI, CG, BH, EH, DG, i.e. 6 in number. Thus, there are 3 + 6 = 9 straight lines in the figure.

The figure may be labelled as shown in the solution image. The horizontal lines are BC, DE, FG, HL, i.e. 4 in number. The vertical lines are AJ, i.e. 1 in number. The slanting lines are AH, AL, CI, BK, EJ, DJ, GK, FI, i.e. 8 in number. Thus, there are 4 + 1 + 8 = 13 straight lines in the figure.

The figure may be labelled as shown in the solution image. The horizontal lines are AD, IL, EF, GH, i.e. 4 in number. The vertical lines are DL, AI, BJ, CK, i.e. 4 in number. The slanting lines are AL, DI, i.e. 2 in number. Thus, there are 4 + 4 + 2 = 10 straight lines in the figure.

The figure may be labelled as shown in the solution image. The triangles are: AFH, AFD, AFE, AHD, ADE, FHD, FHE, HDE, DCB, DCG, CBG. Thus, there are 11 triangles in the figure.

The figure may be labelled as shown in the solution image. The triangles are: AHF, AHG, AHB, AHE, AFG, AFD, AFE, ABD, ABC, ABE, ADC, ADE, HFB, HFD, HFE, HGE, HBD, HDE, FGE, FBD, FBE, BDE, BCE, DCE. Thus, there are 24 triangles in the figure.

The figure may be labelled as shown in the solution image. The triangles are: ACK, ACI, ACF, AKI, AIF, ABF, CKI, CKF, CBG, CBF, CBD, CGD, KIF, KJF, IJE, IJF, IJH, IEH, BFD, JFH. Thus, there are 20 triangles in the figure.

The figure may be labelled as shown in the solution image. The triangles are: AIM, AIK, AMK, ANG, ANH, ACE, ACD, AED, IGJ, MLH, NBF, NBD, NFD, NJL, NJK, NLK, BGC, FEH. Thus, there are 18 triangles in the figure.

The figure may be labelled as shown in the solution image. The triangles are: ACK, AKB, ABD, CKB, CBE, KBE, KBD, KIG, KIH, KGH, BFJ, BFH, BJH, FDG, JIE. Thus, there are 15 triangles in the figure.

The figure may be labelled as shown in the solution image. The triangles are: AJM, ACD, ABD, AEH, MKD, MLD, CKN, CBD, CFI, KLD, DHF, DHG, DFG. Thus, there are 13 triangles in the figure.

The figure may be labelled as shown in the solution image. Squares of size 1 (smallest first): ABFE, DCGH, POKL, MNJI, BCGF, NOKJ, EIJF, HLKG, FJKG, i.e. 9 in number. Squares of size 2 (smallest first): ACKI, DBJL, PNFH, MOGE, i.e. 4 in number. Squares of size 3 (smallest first): ADPM, i.e. 1 in number. Total number of squares = 9 + 4 + 1 = 14.

The figure may be labelled as shown in the solution image. Squares of size 1 (smallest first): DEIH, FEIJ, NMIJ, LMIH, i.e. 4 in number. Squares of size 2 (smallest first): ABIG, CBIK, QPIK, OPIG, DFNL, i.e. 5 in number. Squares of size 3 (smallest first): ACQO, i.e. 1 in number. Total number of squares = 4 + 5 + 1 = 10.

The figure may be labelled as shown in the solution image. Squares of size 1 (smallest first): DEIH, FEIJ, NJIM, LMIH, i.e. 4 in number. Squares of size 2 (smallest first): ABIG, CBIK, QKIP, OPIG, DFNL, i.e. 5 in number. Squares of size 3 (smallest first): BKPG, i.e. 1 in number. Squares of size 4 (smallest first): ACQO, i.e. 1 in number. Total number of squares = 4 + 5 + 1 + 1 = 11.

The figure may be labelled as shown in the solution image. Triangles: BEA, BIC, BIJ, BIF, BCJ, BCF, BJD, ELD, ELK, ELH, ECK, EDK, EDH, ILM, ICJ, ICK, IJF, LJD, LDK, LKH, CJD, CJK, CJF, CJG, CDK, CDG, JDK, JKG, DKG, DKH, i.e. 30 in number. Squares: BIJC, ELKD, CJKD, CFJG, DGKH, i.e. 5 in number. So there are 30 triangles and 5 squares.

The figure may be labelled as shown in the solution image. Triangles: BDH, BDA, BGC, BGH, BGE, BCH, BCE, DIC, DIH, DIF, DCH, DCF, GIC, GIJ, GCH, GHE, ICH, IHF, CHE, CHF, i.e. 20 in number. Squares: BGHC, DIHC, CEHF, i.e. 3 in number. So there are 20 triangles and 3 squares.

The figure may be labelled as shown in the solution image. Triangles: BFA, BKC, BKL, BKG, BCL, BCG, BLD, FOE, FON, FOJ, FDN, FEN, FEJ, KCL, KCM, KLG, OME, OEN, ONJ, CLD, CLM, CLG, CLH, CDM, CDH, CME, LDM, LDN, LMH, DME, DMN, DMH, DMI, DEN, DEI, MEN, MNI, ENI, ENJ, i.e. 39 in number. Squares: BKLC, FONE, CLMD, CGLH, DMNE, DHMI, EINJ, i.e. 7 in number. So there are 39 triangles and 7 squares.

The figure may be labelled as shown in the solution image. Squares of size 1 (smallest first): DFML, HFMN, VTMN, RTML, i.e. 4 in number. Squares of size 2 (smallest first): AEJC, BIKG, PWYU, OSXQ, i.e. 4 in number. Squares of size 3 (smallest first): DHVR, i.e. 1 in number. Total number of squares = 4 + 4 + 1 = 9.

The figure may be labelled as shown in the solution image. Squares of size 1 (smallest first): BCGF, DCGH, LHGK, JKGF, i.e. 4 in number. Squares of size 2 (smallest first): CHKF, i.e. 1 in number. Squares of size 3 (smallest first): BDLJ, i.e. 1 in number. Squares of size 4 (smallest first): AIME, i.e. 1 in number. Total number of squares = 4 + 1 + 1 + 1 = 7.

The figure may be labelled as shown in the solution image. Squares of size 1 (smallest first): EDHI, EFJI, HLMI, JNMI, i.e. 4 in number. Squares of size 2 (smallest first): AEHC, EHMJ, EBGJ, HMPK, JOQM, i.e. 5 in number. Squares of size 3 (smallest first): DFNL, i.e. 1 in number. Total number of squares = 4 + 5 + 1 = 10.

The figure may be labelled as shown in the solution image. There are 13 circles. This is clear from the solution figure, in which the circles have been numbered 1 to 13.

The figure may be labelled as shown in the solution image. There are 10 circles. This is clear from the solution figure, in which the circles have been numbered 1 to 10.

The figure may be labelled as shown in the solution image. There are 13 circles. This is clear from the solution figure, in which the circles have been numbered 1 to 13.

The figure may be labelled as shown in the solution image. Rectangles (squares count as rectangles): AEOK, AEJF, AKLB, AKMC, AKND, AFGB, AFHC, AFID, EOLB, EOMC, EOND, EJGB, EJHC, EJID, OKFJ, OJGL, OJHM, OJIN, KFGL, KFHM, KFIN, BLMC, BLND, BCHG, BDIG, LMHG, LNIG, CMND, CDIH, MNIH, i.e. 30 in number. Hexagons: AEJNLF, ADJOLF, ADJNLF, EJNKFB, EJNLFB, OKFBDJ, OLFBDJ, KFBDJN, FBDJNL, i.e. 9 in number. So there are 30 rectangles and 9 hexagons.

The figure may be labelled as shown in the solution image. Rectangles (squares count as rectangles): BFPL, BFKG, BLMC, BLOE, BLND, BGHC, BGJE, BGID, FPMC, FPOE, FPND, FKHC, FKJE, FKID, PLGK, PKHM, PKJO, PKIN, LGHM, LGJO, LGIN, CMOE, CMND, CEJH, CDIH, MOJH, MNIH, EOND, EDIJ, ONIJ, i.e. 30 in number. Hexagons: AEOQMC, i.e. 1 in number. So there are 30 rectangles and 1 hexagons.

The figure may be labelled as shown in the solution image. Rectangles (squares count as rectangles): AEMI, AIJB, AIKC, AILD, EMJB, EMKC, EMLD, BJKC, BJLD, CKLD, i.e. 10 in number. Hexagons: AEHLJF, ABGKJF, ADHMJF, ADHLJF, EHLIFB, EHLJFB, EHLKGD, MIFBDH, MJFBDH, MLGCDH, IFBCGJ, IFBDHL, BDHLJF, i.e. 13 in number. So there are 10 rectangles and 13 hexagons.