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51.3 we know that time(hours)=___time(mins)___ 60 .: time = __100__= _5_hrs 60 3 then forward, we have to calculate the reduced speed. s=_d_ .: d=38km and t= 5/3 t _38_ __38x3__ = _114_=22.8km/r _5_ = 5 5 3 now, they told that new speed =4/9s (s actuall) s= _114_ x _9_= _1026_ = 51.3kmr 5 4 20 Vaishnavi 11-26-2025 06:11 PM

51.3 we know that time(hours)=___time(mins)___ 60 .: time = __100__= _5_hrs 60 3 then forward, we have to calculate the reduced speed. s=_d_ .: d=38km and t= 5/3 t _38_ __38x3__ = _114_=22.8km/r _5_ = 5 5 3 now, they told that new speed =4/9s (s actuall) s= _114_ x _9_= _1026_ = 51.3kmr 5 4 20 Vaishnavi 11-26-2025 06:11 PM

Wrong Answer To find the actual speed of Amar''s car, we need to use the information given about the speed and distance covered. Let''s denote Amar''s original speed as ?? S km/h. Find the reduced speed: Amar is traveling at 4 9 9 4 ? of his original speed, so his current speed is 4 9 ?? 9 4 ? S. Convert the travel time: Amar covers 38 km in 100 minutes. Convert 100 minutes to hours: 100  minutes = 100 60  hours = 5 3  hours 100 minutes= 60 100 ?  hours= 3 5 ?  hours Set up the distance formula: Distance is equal to speed multiplied by time. Distance = Speed × Time Distance=Speed×Time 38  km = ( 4 9 ?? ) × 5 3  hours 38 km=( 9 4 ? S)× 3 5 ?  hours Solve for the original speed ?? S: 38 = ( 4 9 ?? ) × 5 3 38=( 9 4 ? S)× 3 5 ? 38 = 4 × 5 9 × 3 ?? 38= 9×3 4×5 ? S 38 = 20 27 ?? 38= 27 20 ? S ?? = 38 × 27 20 S=38× 20 27 ? ?? = 38 × 1.35 S=38×1.35 ?? = 51.3  km/h S=51.3 km/h Nihal Ahmed N 07-5-2024 08:27 AM

50.80 given, case one,d=38km t=100m=100*1/60hr=5/3hr so, speed=d/t=38*3/5=22.8kmph for 4/9th it is at 22.8kmph, then for 8/9th it is 45.6kmph for 1 part speed is = 22.8/4=5.7kmph then whole speed is, 45.6+5.7 = 51.3 approx == 50.80 Mohan reddy 07-19-2022 05:55 AM

wrong answer s=D/T >> 4s/9=(38*60)/100>> s=(38*60*9)/(100*4)>> s=51.30kmph Krishna Kumar 05-31-2017 02:56 AM

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