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If a number is divisible by a number, is it always divisible by factors of that number. Since 10 is a factor of 80, 653xy is divisible by 10. It means last digit,y =0 Rewriting 653xy as 653x0. Since 8 is a factor of 80, 653x0 is divisible by If a number is divisible by a number, is it always divisible by factors of that number. Since 10 is a factor of 80, 653xy is divisible by 10. It means last digit,y =0 Rewriting 653xy as 653x0. Since 8 is a factor of 80, 653x0 is divisible by 8. It means last three digits 3x0 is divisible by 8. Hence, x is 2 or 6 if x=2, number is 65320. But this is not divisible by 80 if x=6, number is 65360 which is divisible by 80 Therefore number is 65360 with x=6 and y=0. x+y = 6+0 = 6 Alternative Solution 65300/80 = 816 with remainder = 20. Therefore, 65300 + 60 = 65360 is divisible by 80. In this case xy = 60. There are no other values of xy which makes 653xy divisible by 80 (If we add another 80 to 65360, number becomes 65440 which cannot be taken) Hence, x+y = 6+0 = 6 Naveen Kumar 08-20-2018 05:00 AM

Correct Answer It must be 4 (X = 4 and Y=0) Curious 11-26-2017 08:35 PM

doubt give the solution fr ths question Myvizhi.M 01-4-2017 12:03 AM

explain it what is the solution pooma 09-9-2016 12:24 AM

doubt give the solution for this question sravani 08-6-2014 06:01 AM

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