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If x and y are two digits of a number such that the number 6538xy is divisible by 80 then minimum value of sum of x and y is:
Options
- 0
- 8
- 10
- None
CORRECT ANSWER : 0
Discussion Board
If a number is divisible by a number, is it always divisible by factors of that number. Since 10 is a factor of 80, 653xy is divisible by 10. It means last digit,y =0 Rewriting 653xy as 653x0. Since 8 is a factor of 80, 653x0 is divisible by
If a number is divisible by a number, is it always divisible by factors of that number.
Since 10 is a factor of 80, 653xy is divisible by 10. It means last digit,y =0
Rewriting 653xy as 653x0. Since 8 is a factor of 80, 653x0 is divisible by 8. It means last three digits 3x0 is divisible by 8. Hence, x is 2 or 6
if x=2, number is 65320. But this is not divisible by 80
if x=6, number is 65360 which is divisible by 80
Therefore number is 65360 with x=6 and y=0.
x+y = 6+0 = 6
Alternative Solution
65300/80 = 816 with remainder = 20.
Therefore, 65300 + 60 = 65360 is divisible by 80.
In this case xy = 60. There are no other values of xy which makes 653xy divisible by 80 (If we add another 80 to 65360, number becomes 65440 which cannot be taken)
Hence, x+y = 6+0 = 6
Naveen Kumar 08-20-2018 05:00 AM
Correct Answer
It must be 4 (X = 4 and Y=0)
Curious 11-26-2017 08:35 PM
doubt
give the solution fr ths question
Myvizhi.M 01-4-2017 12:03 AM
explain it
what is the solution
pooma 09-9-2016 12:24 AM
doubt
give the solution for this question
sravani 08-6-2014 06:01 AM
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