A five digit number divisible by 3 is to be formed using the numerals 0, 1, 2, 3, 4 and 5, without repetition. The total number of ways in which this can be done is

Options
- 216
- 240
- 600
- 3125

CORRECT ANSWER : 216

Discussion Board
216

We know that a number is divisible by 3 if the sum of its digits is divisible by 3
Now the sum of the digits 1,2,3,4 is 15 which is divisible by 3
? All the five digit numbers formed by the digits 1,2,3,4,5 are divisible by 3 and their number =5!=120
When we include 0, the four other digits whose sum is divisible by 3 are 1,2,4 and 5
? The number of numbers in this case =4×4!=4×24=96
Hence, the total number of ways =96+120=216

ASHISH CHAURASIYA 08-3-2023 02:10 PM

how

what is the logic

veni 09-6-2014 05:05 AM

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